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nikklg [1K]
3 years ago
6

What mechanism of energy is transferred by mass motion of fluid from one region of space to another?​

Physics
1 answer:
lora16 [44]3 years ago
5 0
Convection, because it is the process of heat transfer from one location to the next by the movement of fluids. The moving fluid carries energy within it.
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To 3 significant digits, what is the period of the pendulum using the equation for the period of a simple pendulum? Hint, the in
netineya [11]

Answer:

1.42 seconds

Explanation:

T=2*pi*(sqrt length over gravity)

T=2*pi*(sqrt 0.5/9.8)

T=1.4189

Round to 3 significant digits

T=1.42 seconds

3 0
3 years ago
A 70 kilogram mountaineer is standing on the summit of Mt. Everest. The distance between the mountaineer and the center of Earth
Vilka [71]
F = GMm/r² 
F = (6.673*10^-11)(5.98*10^24)(70)/(6.39*10^... 
F = 684 N (3sf)
5 0
3 years ago
Read 2 more answers
Two forces, F1 and F2, are at an angle Θ. The magnitude of F1 is 2 dynes and that of F2 is 3 dynes. If the magnitude of the resu
Igoryamba

Answer:

75.5°

Explanation:

If we say F₁ is horizontal (0°), and F₂ is at angle θ, then the components are:

F₁ₓ = 2

F₁ᵧ = 0

F₂ₓ = 3 cos θ

F₂ᵧ = 3 sin θ

So the components of the resultant vector are:

Rₓ = 2 + 3 cos θ

Rᵧ = 3 sin θ

We know the magnitude of R, so using Pythagorean theorem:

4² = (2 + 3 cos θ)² + (3 sin θ)²

16 = 4 + 12 cos θ + 9 cos² θ + 9 sin² θ

16 = 4 + 12 cos θ + 9

3 = 12 cos θ

cos θ = 1/4

θ ≈ 75.5°

Alternatively, you can draw a diagram and use law of cosine to find the internal angle, then subtract from 180 to find θ.

5 0
3 years ago
ACUTE INFECTION plz help worth 70 pt plz help !!!!! Also brainlest
Paraphin [41]

Answer:

Simple awnser Do it yourself I really would help but I have no clue! Sorry

Explanation:

3 0
3 years ago
A woman of mass 44 kg jumps off the bow of
Aneli [31]

Answer:

v₃ = 1.59 [m/s]

Explanation:

In order to solve this problem, we must use the principle of conservation of linear momentum.

That is, the momentum is conserved before and after the jump.

Before the jump, we have the mass of the woman and the canoe without speed (at rest). After the jump you have the woman moving to the right and the canoe moving to the left.

(m_{1}+m_{2})*v_{1}=(m_{1}*v_{2})-(m_{2}*v_{3})

where:

m₁ = mass of the woman = 44 [kg]

m₂ = mass of the canoe = 69 [kg]

v₁ = velocity of the canoe at rest = 0

v₂ = velocity of the woman after jumping = 2.5 [m/s]

v₃ = velocity of the canoe after jumping = [m/s]

(44+69)*0= (44*2.5)-(69*v_{3})\\110 = 69*v_{3}\\v_{3}=1.59[m/s]

4 0
3 years ago
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