Answer:
1.42 seconds
Explanation:
T=2*pi*(sqrt length over gravity)
T=2*pi*(sqrt 0.5/9.8)
T=1.4189
Round to 3 significant digits
T=1.42 seconds
F = GMm/r²
F = (6.673*10^-11)(5.98*10^24)(70)/(6.39*10^...
F = 684 N (3sf)
Answer:
75.5°
Explanation:
If we say F₁ is horizontal (0°), and F₂ is at angle θ, then the components are:
F₁ₓ = 2
F₁ᵧ = 0
F₂ₓ = 3 cos θ
F₂ᵧ = 3 sin θ
So the components of the resultant vector are:
Rₓ = 2 + 3 cos θ
Rᵧ = 3 sin θ
We know the magnitude of R, so using Pythagorean theorem:
4² = (2 + 3 cos θ)² + (3 sin θ)²
16 = 4 + 12 cos θ + 9 cos² θ + 9 sin² θ
16 = 4 + 12 cos θ + 9
3 = 12 cos θ
cos θ = 1/4
θ ≈ 75.5°
Alternatively, you can draw a diagram and use law of cosine to find the internal angle, then subtract from 180 to find θ.
Answer:
Simple awnser Do it yourself I really would help but I have no clue! Sorry
Explanation:
Answer:
v₃ = 1.59 [m/s]
Explanation:
In order to solve this problem, we must use the principle of conservation of linear momentum.
That is, the momentum is conserved before and after the jump.
Before the jump, we have the mass of the woman and the canoe without speed (at rest). After the jump you have the woman moving to the right and the canoe moving to the left.

where:
m₁ = mass of the woman = 44 [kg]
m₂ = mass of the canoe = 69 [kg]
v₁ = velocity of the canoe at rest = 0
v₂ = velocity of the woman after jumping = 2.5 [m/s]
v₃ = velocity of the canoe after jumping = [m/s]
![(44+69)*0= (44*2.5)-(69*v_{3})\\110 = 69*v_{3}\\v_{3}=1.59[m/s]](https://tex.z-dn.net/?f=%2844%2B69%29%2A0%3D%20%2844%2A2.5%29-%2869%2Av_%7B3%7D%29%5C%5C110%20%3D%2069%2Av_%7B3%7D%5C%5Cv_%7B3%7D%3D1.59%5Bm%2Fs%5D)