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solong [7]
3 years ago
11

Which of the expressions (on the photo document I inserted) together represent all solutions to the following equation?

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
7 0

Answer:

x =15 + 30n

Step-by-step explanation:

8cos(12x)+4=-4

Subtract 4 from each side

8cos(12x)+4-4=-4-4

8cos(12x)=-8

Divide by 8

8/8cos(12x)=-8/8

cos(12x) = -1

Take the arccos on each side

arccos(cos(12x)) = arccos(-1)

12x = 180 degrees  

But we can go around in a circle of 360 and get the same result

12 x = 180+360n  where n is an integer

Divide each side by 12

x = 180/12 +360n/12

x =15 + 30n

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How many triangles can be made with a 70 degree angle a 30 degree angle and an 80 degree angle​
uranmaximum [27]

Answer:

There are infinite number of triangles that could be achieved with those angles.

To picture this, we only have to imagine a triangle that is either smaller or bigger than the one at hand.

Tracing a series of paralell lines (which guarantee that the angles are being kept),  we can draw triangles for infinite values of x,y and z.

5 0
3 years ago
Help pleaseeeeee!
marin [14]

Answer:

Horizontal shift of 1 unit to the right, a vertical shift upward of 6 units, and a vertical stretch by a factor of 3 ..

Step-by-step explanation:

Given function is:

3[|x-1|+2]

Can also be written as:

3|x-1|+6

As we can see that the -1 is grouped with x which means it is a horizontal shift of 1 unit to the right.

Now, 6 is added to the function and it is not grouped with x which means that there is a vertical shift of 6 units upward.

Lastly, 3 is multiplied with the term containing x which means that there is a vertical stretch of 3 units.

Hence, the correct option is:

Horizontal shift of 1 unit to the right, a vertical shift upward of 6 units, and a vertical stretch by a factor of 3 ..

4 0
3 years ago
Read 2 more answers
use the intermediate value theorem to determine whether the following equation has a solution or not x^3-3x-1
xxTIMURxx [149]

Answer:

Yes, this equation has a solution. According to Intermediate Value Theorem at least one solution for [0,2]

Step-by-step explanation:

Hi there!

1) Remember a definition.

Intermediate Value Theorem:

If f is continuous on a given closed interval [a,b], and f(a)≠f(b) and f(a)<k<f(b) then there has to be at least one number 'c' between 'a' and 'b', such that f(c)=k

----

(Check the first graph as an example)

2) The Intermediate Value Theorem can be applied to determine whether there is a solution on a given interval.

Let's choose the interval [0,2]

f(x)=x^{3}-3x-1\\f(0)=(0)^{3}-3(0)-1\\f(0)=-1\\f(0)

Proceed to the other point: 2

f(x)=x^{3}-3x-1\\f(2)=(2)^{3}-3(2)-1\\f(2)=1\\f(2)>0\\

3) Check the 2nd Graph for a the Visual answer, of it.  And the 3rd graph for all solutions of this equation.

3 0
3 years ago
D) Matthew travels two and one-half miles to get to
Fudgin [204]

Answer:

5/6 miles

Step-by-step explanation:

Matthews travels 2.5 miles → this is 3 times the distance that Jennifer travels

Jennifer travels 2.5 / 3 miles  = 5/6 miles

because,

2.5 =  2 and 1/2 = 5/2

(5/2) ÷ 3 = (5/2) *(1/3) = 5*1/ 2*3 = 5/6

5 0
3 years ago
Avani wrote the linear equation y = 5 x + 4. Then, she wrote the equation of the line that is perpendicular to y = 5 x + 4 and t
Margarita [4]

Avani wrote the linear equation y = 5x + 4. Then, she wrote the equation of the line that is perpendicular to y = 5x+ 4 and that passes through (15,–2). If her new equation is in the form  y-\frac{1}{5}x+b, what is the value of b?

\bf y=mx+b

  • m is the slope
  • b is the y-intercept

The equation of a line that is perpendicular to another line always has the opposite reciprocal slope. In the original equation, the slope is 5. The opposite of 5, which refers to the sign, is -5. The reciprocal of -5 is -1/5. That means the slope of the new line is -1/5.

The perpendicular line:

  • Has a slope of -\frac{1}{5}
  • Passes through the point (15, -2)

To find the equation of a line that passes through a specific point, you need to use slope-intercept form.

\bf y-y_{1} =m(x-x_{1})

  • y₁ is the y-value of the point
  • m is the slope
  • x₁ is the x-value of the point

y₁ is -2, m is -1/5,  and x₁ is 15.

Substitute the known values into the equation:

y-(-2)=-\frac{1}{5}(x-15) \rightarrow y+2= -\frac{1}{5}(x-15)

Open the parentheses and distribute:

-\frac{1}{5}(x-15) \rightarrow -\frac{1}{5} \cdot x\ +  -\frac{1}{5} \cdot -15 \rightarrow -\frac{1}{5}x +3

The new equation will be:

y+2=-\frac{1}{5}x+3

Lastly, you need to move the positive 2 to the other side to keep it in y = mx + b form.

y+2-2=-\frac{1}{5}x+3-2 \rightarrow y=-\frac{1}{5}x+1

The equation of the perpendicular line is:

\bf y=-\frac{1}{5}x+1

The value of b is 1.

5 0
3 years ago
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