Answer:
2.5
type A/B
Step-by-step explanation:
10/2.5=4
15/6=2.5
18/7.2=2.5
In each table, the x-values differ by 6. A linear function will also have a constant difference of y-values. Only the 4th table has that.
(x, y) = (-6, -3), (0, 2), (6, 7), (12, 12)
_____
An increase in x by 6 produces an increase in y by 5. The slope of this linear function is 5/6. In slope-intercept form, the equation is y = (5/6)x + 2.
From the given mean and margin of error, the 99% confidence interval for the mean amount of money spent on lunch per week for all students is:
[$19.5, $22.5].
<h3>How to calculate a confidence interval given the sample mean and the margin of error?</h3>
The confidence interval is given by the sample mean plus/minus the margin of error, hence:
- The lower bound is the sample mean subtracted by the margin of error.
- The upper bound is the sample mean added to the margin of error.
For this problem, we have that:
- The sample mean is of $21.
- The margin of error is of $1.50.
Hence the bounds are given as follows:
- Lower bound: 21 - 1.50 = $19.50.
- Upper bound: 21 + 1.50 = $22.50.
Hence the interval is [$19.50, $22.50].
More can be learned about confidence intervals at brainly.com/question/25890103
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This problem requires the use of the chain rule: dy / dt = [dy / dx] * [dx / dt]
y = √x => dy / dx = 1 / (2√x)
<span>(a) Find dy/dt, given x = 16 and dx/dt = 7.
dy/dt = [ 1/(2√x) ] * 7 = [1/(2*4)] * 7 = 7/8
(b) Find dx/dt, given x = 64 and dy/dt = 8.
dx/dt = [dy/dt] / [dy/dx] = 8 / [1/(2√64) ] = 128
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