.1 Simplify: 5n(2n3+n2+8)+n(4-n).
Solution:
5n(2n3+n2+8)+n(4-n).
= 5n × 2n3 + 5n × n2 + 5n × 8 + n × 4 - n × n.
= 10n4 + 5n3 + 40n + 4n – n2.
= 10n4 + 5n3 + 44n – n2.
= 10n4 + 5n3 – n2 + 44n.
Answer: 10n4 + 5n3 – n2 + 44n
Any number to the power 0 is 1.
So 10^0 = 1
Answer:
6 quarters, 3 dimes, and 12 nickles
Step-by-step explanation:
Let's say Q is the number of quarters, D is the number of dimes, and N is the number of nickles.
From the information in the problem, we can write three equations:
25Q + 10D + 5N = 240
N = 2Q
Q = 2D
Solve the system of equations using substitution.
25(2D) + 10D + 5(2Q) = 240
50D + 10D + 10Q = 240
60D + 10(2D) = 240
60D + 20D = 240
80D = 240
D = 3
Q = 6
N = 12
There are 6 quarters, 3 dimes, and 12 nickles.
Answer:
10,0
Step-by-step explanation:
this is because when you plot the points they are 10 apart and on the same level
