The point-slope form of the equation for a line through point (h, k) with slope m is ...
y - k = m(x - h)
For your given point and slope, this equation is
y + 1 = -1(x + 10)
-2(x+5) OR 2(-x-5) I hope that helps if not please let me know!
It should be a 100 degree angle as well.
Step-by-step explanation:
x=30° { ins angle inscribed angle Standing on arc are equal }
hope it helps
<h2>stay safe healthy and happy...</h2>
Find the slope of this line
slope=(y2-y1)/(x2-x1)
slope=(-9-(-4))/(0-(-3))=(-9+4)/(3)=-5/3
yint is y=-9
y=mx+b
y=-5/3x-9
parllell means has same slope
y=-5/3x+b
find b by inputing point
(3,-7)
(x,y)
x=3
y=-7
-7=-5/3(3)+b
-7=-5+b
add 5
-2=b
the equation of the line is y=-5/3x-2
