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Viktor [21]
2 years ago
15

John left a $2 tip for the server when stopped at a diner. If this was 20% of his order total, how much was his order?

Mathematics
2 answers:
Katen [24]2 years ago
4 0
The answer is 10 dollars
Alona [7]2 years ago
4 0

Answer:

$8

Step-by-step explanation:

I am not 100% sure but im like 89% sure but just try it

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What is a solution of the inequality shown below? -6 + b ≥ -6​
KiRa [710]

Answer:

Solution given;

-6 + b ≥ -6

adding 6 on both side

-6+6+b≥-6+6

<u>b</u><u>≥</u><u>0</u>

6 0
3 years ago
Read 2 more answers
5x+3x=420 12x+9=1080 What does x and y equal?
Korvikt [17]

Answer:

8x-55818-t

Step-by-step explanation:

7 0
2 years ago
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Evaluate <br> 12^2<br><br> 1. 144<br> 2. 24<br> 3. 266
pogonyaev

Answer:

The answer is 144

Step-by-step explanation:

12*12

12²

144

6 0
2 years ago
Show that if X is a geometric random variable with parameter p, then
Lubov Fominskaja [6]

Answer:

\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}=-\frac{p ln p}{1-p}

Step-by-step explanation:

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

P(X=x)=(1-p)^{x-1} p

Let X the random variable that measures the number os trials until the first success, we know that X follows this distribution:

X\sim Geo (1-p)

In order to find the expected value E(1/X) we need to find this sum:

E(X)=\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}

Lets consider the following series:

\sum_{k=1}^{\infty} b^{k-1}

And let's assume that this series is a power series with b a number between (0,1). If we apply integration of this series we have this:

\int_{0}^b \sum_{k=1}^{\infty} r^{k-1}=\sum_{k=1}^{\infty} \int_{0}^b r^{k-1} dt=\sum_{k=1}^{\infty} \frac{b^k}{k}   (a)

On the last step we assume that 0\leq r\leq b and \sum_{k=1}^{\infty} r^{k-1}=\frac{1}{1-r}, then the integral on the left part of equation (a) would be 1. And we have:

\int_{0}^b \frac{1}{1-r}dr=-ln(1-b)

And for the next step we have:

\sum_{k=1}^{\infty} \frac{b^{k-1}}{k}=\frac{1}{b}\sum_{k=1}^{\infty}\frac{b^k}{k}=-\frac{ln(1-b)}{b}

And with this we have the requiered proof.

And since b=1-p we have that:

\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}=-\frac{p ln p}{1-p}

4 0
3 years ago
Anyone know how to solve this?
Viktor [21]
Calculate the volume of the cylinder in square feet.
Pi•r^2•h
3.14•2^2•6
3.14•4•6
3.14•24


Then multiply by 62.5 lbs/ft^2
3.14•24•62.5
3 0
2 years ago
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