All categories

2 years ago

Choose the equation below that represents the line passes to the point (7,-2) an the slope of -3

Mathematics

1 answer:

katrin [286]2 years ago

8 0

Hello there!
The answer is c because the equation that is being used is point-slope, which is:
y-y1=m(x-x1)
hope this helps

You might be interested in

Cathy did a survey in four bird parks and wrote the following observations: park p number of green birds 18 total number of bird

Nutka1998 [239]

Park p :
18/82 = 0.219 = 21.9% green birds

park q :
39/88 = 0.443 = 44.3% green birds

park r :
38/64 = 0.593 = 59.3% green birds

park service :
22/50 = 0.44 = 44%

park with greatest percentage of green birds is park r <==

3 0

2 years ago

Read 2 more answers

Asaph took out a loan for $17,550. To pay it back, he will make 60 monthly payments of $437.

alexira [117]

Total payments 437×60=26,220
Interest paid
26,220−17,550=8,670

7 0

2 years ago

Read 2 more answers

Simplify y^-2/y^-7. Write your answer with a positive exponent only.

attashe74 [19]

Answer:

y^5

Step-by-step explanation:

y^-2/y^-7

When we divide exponents with the same base, we subtract the exponents

y^ ( -2 - -7)

y^ ( -2+7)

y^ 5

4 0

3 years ago

Read 2 more answers

A soccer ball kicked from the ground with an initial velocity of 32 ft/s is given by the function

Greeley [361]

Answer:

In words the answer is between t=0 and t=2.

In interval notation the answer is (0,2)

In inequality notation the answer is 0<t<2

Big note: You should make sure the function I use what you meant.

Step-by-step explanation:

I hope the function is h(t)=-16t^2+32t because that is how I'm going to interpret it.

So if we can find when the ball is on the ground or has hit the ground (this is when h=0) then we can find when it is in the air which is between those 2 numbers.

0=-16t^2+32t

0=-16t(t-2)

So at t=0 and t=2

So the ball is in the air between t=0 and t=2

Interval notation (0,2)

Inequality notation 0<t<2

6 0

3 years ago

Read 2 more answers

For 0 ≤ ϴ < 2π, how many solutions are there to tan(StartFraction theta Over 2 EndFraction) = sin(ϴ)? Note: Do not include va

Black_prince [1.1K]

Answer:

3 solutions:

$\theta={0, \frac{\pi}{2}, \frac{3\pi}{2}}$

Step-by-step explanation:

So, first of all, we need to figure the angles that cannot be included in our answers out. The only function in the equation that isn't defined for some angles is $tan(\frac{\theta}{2})$ so let's focus on that part of the equation first.

We know that:

$tan(\frac{\theta}{2})=\frac{sin(\frac{\theta}{2})}{cos(\frac{\theta}{2})}$

therefore:

$cos(\frac{\theta}{2})\neq0$

so we need to find the angles that will make the cos function equal to zero. So we get:

$cos(\frac{\theta}{2})=0$

$\frac{\theta}{2}=cos^{-1}(0)$

$\frac{\theta}{2}=\frac{\pi}{2}+\pi n$

$\theta=\pi+2\pi n$

we can now start plugging values in for n:

$\theta=\pi+2\pi (0)=\pi$

if we plugged any value greater than 0, we would end up with an angle that is greater than $2\pi$ so, that's the only angle we cannot include in our answer set, so: