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3 years ago

What is [(6.2x8.4) minus 9.28]

Mathematics

2 answers:

igor_vitrenko [27]3 years ago

8 0

The answer is 42.8

I hope that helps

asambeis [7]3 years ago

3 0

I agree that the answer would be 42.8 so now you can be sure of it :)

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Find the difference. ( 3 - 2x + 2<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x

goldfiish [28.3K]

The answer is d, laminuos now has to go to Britain to disconcerted what was right.

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3 years ago

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Large cheese pizzas cost 5$ each and large 1 toping pizzas cost 6$ each. Write an equation that represents the total cost, T of

Tasya [4]

Answer:

T = 5C + 6D

Step-by-step explanation:

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3 years ago

HEY GUYS I NEED HELP WITH THIS PLZZ! write down everything from the detail of how yall found ur answer plzz! 20 points or more..

aleksley [76]

Answer:

1/6+1/8+$13.50+$5=x

x=$18.79

Step-by-step explanation:

i add them

first i find the common denominator for 1/6 and 1/8

then i add 13.50 by 5

then add 18.50 by 7/24

i hope this explains how i got my answer

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4 years ago

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At its closest distance, the moon is approximately 3.6 × 105 km from Earth. Mars, at its closest distance, is approximately 5.57

ira [324]

Answer:

The answer is 5.534 x107km

Step-by-step explanation:

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4 years ago

Which expression is a cube root of -1+i√3?

Tpy6a [65]

Answer:

The correct option is C.

Step-by-step explanation:

Root Of Complex Numbers

If a complex number is expressed in polar form as

$Z=(r,\theta)$

Then the cubic roots of Z are

$\displaystyle Z_1=\left(\sqrt[3]{r},\frac{\theta}{3}\right)$

$\displaystyle Z_2=\left(\sqrt[3]{r},\frac{\theta}{3}+120^o\right)$

$\displaystyle Z_3=\left(\sqrt[3]{r},\frac{\theta}{3}+240^o\right)$

We are given the complex number in rectangular components

$Z=-1+i\sqrt{3}$

Converting to polar form

$r=\sqrt{(-1)^2+(\sqrt{3})^2}=2$

$\displaystyle tan\theta=\frac{\sqrt{3}}{-1}=-\sqrt{3}$

It's located in the second quadrant, so

$\theta=120^o$

The number if polar form is

$Z=(2,120^o)$

Its cubic roots are

$\displaystyle Z_1=\left(\sqrt[3]{2},\frac{120^o}{3}\right)=\left(\sqrt[3]{2},40^o\right)$

$\displaystyle Z_2=\left(\sqrt[3]{2},40^o+120^o\right)=\left(\sqrt[3]{2},160^o\right)$

$\displaystyle Z_3=\left(\sqrt[3]{2},40^o+240^o\right)=\left(\sqrt[3]{2},280^o\right)$

Converting the first solution to rectangular coordinates

$z_1=\sqrt[3]{2}(\ cos40^o+i\ sin40^o)$

The correct option is C.

8 0

4 years ago