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ANTONII [103]
4 years ago
11

10 of 16 students in Bob's Class are girls. His teacher selected two helpers by randomly drawing names. he drew a boy's name fir

st and then a girl's name. Bob thinks that the probability of this happening is 15 / 64 is he correct? If not explain his error
Mathematics
1 answer:
ehidna [41]4 years ago
7 0
<h2>He is right...I guess? maybe maybe not?</h2>
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Simplify (7 1/5)5<br> Please show work
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7 ^ 1/5 ^ 5

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7 ^ (1/5 *5)

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The volume of a sphere is 36 ft.3 What is the radius of the sphere? Use
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3 years ago
Let M be the set of all nxn matrices. Define a relation on won M by A B there exists an invertible matrix P such that A = P BP S
Sophie [7]

Answer:

Recall that a relation is an <em>equivalence relation</em> if and only if is symmetric, reflexive and transitive. In order to simplify the notation we will use A↔B when A is in relation with B.

<em>Reflexive: </em>We need to prove that A↔A. Let us write J for the identity matrix and recall that J is invertible. Notice that A=J^{-1}AJ. Thus, A↔A.

<em>Symmetric</em>: We need to prove that A↔B implies B↔A. As A↔B there exists an invertible matrix P such that A=P^{-1}BP. In this equality we can perform a right multiplication by P^{-1} and obtain AP^{-1} =P^{-1}B. Then, in the obtained equality we perform a left multiplication by P and get PAP^{-1} =B. If we write Q=P^{-1} and Q^{-1} = P we have B = Q^{-1}AQ. Thus, B↔A.

<em>Transitive</em>: We need to prove that A↔B and B↔C implies A↔C. From the fact A↔B we have A=P^{-1}BP and from B↔C we have B=Q^{-1}CQ. Now, if we substitute the last equality into the first one we get

A=P^{-1}Q^{-1}CQP = (P^{-1}Q^{-1})C(QP).

Recall that if P and Q are invertible, then QP is invertible and (QP)^{-1}=P^{-1}Q^{-1}. So, if we denote R=QP we obtained that

A=R^{-1}CR. Hence, A↔C.

Therefore, the relation is an <em>equivalence relation</em>.

4 0
3 years ago
I got the first part but cant figure out the second, help would be appreciated
azamat

Answer:

see explanation

Step-by-step explanation:

look at the explanation& answer photo

6 0
3 years ago
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