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maksim [4K]
3 years ago
12

Richard Hoskins was the leader of a 4-H club with 27 children. When he divided the club into groups of 5 to play a game, how man

y groups did he have? How many extra children were there?
Mathematics
1 answer:
kotykmax [81]3 years ago
4 0

Answer:

5 groups

2 extra children

Step-by-step explanation:

The computation of a number of groups and number of extra children is shown below:

Given that

There is 27 children

And, this group would be divided into group 5

So,

As we know that 25 is easily divided by 5

So there are 5 groups

And, the extra children is

= 27 - 25

= 2 chidren

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~**Will mark brainliest **~<br> For the correct answers to all three questions
aleksandr82 [10.1K]

a)

\dfrac{42}{65}\cdot\dfrac{25}{36}\cdot\dfrac{26}{49}=\dfrac{2\cdot3\cdot7}{5\cdot13}\cdot\dfrac{5\cdot5}{2\cdot2\cdot3\cdot3}\cdot\dfrac{2\cdot13}{7\cdot7}=\dfrac{7}{13}\cdot\dfrac{5}{2\cdot3}\cdot\dfrac{2\cdot13}{7\cdot7}=\\\\\\=\dfrac{1}{1}\cdot\dfrac{5}{2\cdot3}\cdot\dfrac{2}{7}=\dfrac{5}{3}\cdot\dfrac{1}{7}=\dfrac{5}{21}

b)

\dfrac{21}{32}\cdot\dfrac{39}{120}\cdot\dfrac{40}{65}=\dfrac{21}{32}\cdot\dfrac{3\cdot13}{2\cdot2\cdot2\cdot3\cdot5}\cdot\dfrac{2\cdot2\cdot2\cdot5}{5\cdot13}=\\\\\\=\dfrac{3\cdot7}{32}\cdot\dfrac{13}{2\cdot2\cdot2\cdot5}\cdot\dfrac{2\cdot2\cdot2}{13}=\dfrac{21}{32}\cdot\dfrac{1}{5}\cdot\dfrac{1}{1}=\dfrac{21}{160}

c)

\dfrac{15}{90}\cdot\dfrac{36}{75}\cdot\dfrac{27}{42}=\dfrac{3\cdot5}{2\cdot3\cdot3\cdot5}\cdot\dfrac{2\cdot2\cdot3\cdot3}{3\cdot5\cdot5}\cdot\dfrac{3\cdot3\cdot3}{2\cdot3\cdot7}=\\\\\\=\dfrac{1}{2\cdot3}\cdot\dfrac{2\cdot2\cdot3}{5\cdot5}\cdot\dfrac{3\cdot3}{2\cdot7}=\dfrac{1}{1}\cdot\dfrac{2}{5\cdot5}\cdot\dfrac{3\cdot3}{2\cdot7}=\dfrac{1}{25}\cdot\dfrac{9}{7}=\dfrac{9}{175}

6 0
3 years ago
Help meeee!!!!!!!!!!!!!!!!!!!
Ivenika [448]

Answer:

Y=-2x

When x= -6 then y =12

Step-by-step explanation:

If y and x in direct variation then y=c*x for some constant c.

We are told

-4=c2

——> c= -2

So y= -2x

When x= -6 this becomes

Y= (-2) * (-6)

——> y = 12


8 0
3 years ago
Which choice is equivalent to the expression shown below? -3(3y-2x) +2(5x-4y)
kap26 [50]

Answer:

-17y + 16x

Step-by-step explanation:

-3(3y - 2x) + 2(5x - 4y) = -9y + 6x + 10x - 8y = -17Y + 16X.

If it is helpful, plz give me Brainliest.

7 0
3 years ago
Find the sumofthe geometrical progression of five terms, of which the first term is 7 and the multiplier is 7.Verify that the su
777dan777 [17]

Answer:

The sum of first five term of GP is 19607.

Step-by-step explanation:

We are given the following in the question:

A geometric progression with 7 as the first term and 7 as the common ration.

a, ar, ar^2,...\\a  = 7\\r = 7

7, 7^2, 7^3, 7^4...

Sum of n terms in a geometric progression:

S_n = \displaystyle\frac{a(r^n - 1)}{(r-1)}

For sum of five terms, we put n= 5, a = 7, r = 7

S_5 = \displaystyle\frac{7(7^5 - 1)}{(7-1)}\\\\S_5 = 19607

The sum of first five term of GP is 19607.

Verification:

2801\times 7 = 19607

Thus, the sum is equal to product of 2801 and 7.

7 0
3 years ago
15. If R is the midpoint of OS, OR = 8x - 51 and RS = 3x - 6, find QS.
Vikki [24]

Answer:

if you mean find OS, then:

OS = 42

Step-by-step explanation:

if you mean find OS, then:

8x-51 = 3x-6

5x = 45

x = 9

OS = 2(3x-6)

OS = 6x-12

substitute for x

OS = 6(9)-12 =42

8 0
3 years ago
Read 2 more answers
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