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maksim [4K]
3 years ago
12

Richard Hoskins was the leader of a 4-H club with 27 children. When he divided the club into groups of 5 to play a game, how man

y groups did he have? How many extra children were there?
Mathematics
1 answer:
kotykmax [81]3 years ago
4 0

Answer:

5 groups

2 extra children

Step-by-step explanation:

The computation of a number of groups and number of extra children is shown below:

Given that

There is 27 children

And, this group would be divided into group 5

So,

As we know that 25 is easily divided by 5

So there are 5 groups

And, the extra children is

= 27 - 25

= 2 chidren

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9(2a – b)2 – 4(2a – b) – 13
elena-s [515]
18(2a-b)-4(2a-b)-13
=36a-18b-8a+4b-13
Rearrange
=36a-8a-18b+4b-13
=28a-14b-13
3 0
3 years ago
Help.
Zinaida [17]

Answer:

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4 0
3 years ago
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Find the volume.<br> 15 points
Anton [14]

Answer:

the volume is 196

Step-by-step explanation:

17x8=136

6x10=60

136+60=196

3 0
3 years ago
When a number is decreased by 3.5%, the result is 91 what is the original number to the nearest tenth
sdas [7]

Answer:

87.8

Step-by-step explanation:

So you have to multiply 91 times 3.5 which equals 318.5

                      91 × 3.5 = 318.5

Then divide 318.5 by 100 which equals 3.185

                      318.5 ÷ 100 = 3.185

Next subtract 91 by 3.185 which equals 87.815

                      91 - 3.185 = 87.815

Last Round 87.815 to 87.8

                       87.8 should be the answer

Hope this helps

4 0
3 years ago
Read 2 more answers
Which of the following best completes the proof showing that ΔWXZ ~ ΔXYZ?
skelet666 [1.2K]

Angles formed by the segment \overline{XZ} in the triangles ΔWXZ, and ΔXYZ, are equal and the given corresponding sides are proportional.

  • The option that best completes the proof showing that ΔWXZ ~ ΔXYZ is; <u>16 over 12 equals 12 over 9</u>

Reasons:

The proof showing that ΔWXZ ~ ΔXYZ is presented as follows;

Segment \overline{XZ} is perpendicular to segment \overline{WY}

∠WZX and ∠XZY are right angles by definition of \overline{XZ}  perpendicular to \overline{WY}

∠WZX in ΔWXZ = ∠XZY in ΔXYZ = 90° (definition)

\displaystyle \frac{WZ}{XZ} = \frac{16}{12} = \mathbf{ \frac{4}{3}}

\displaystyle \mathbf{ \frac{XZ}{ZY}}  = \frac{12}{9}  = \frac{4}{3}

Therefore;

  • \displaystyle \frac{16}{12} = \frac{12}{9}, which gives, \displaystyle \mathbf{\frac{WZ}{XZ} }= \frac{XZ}{ZY}

Given that two sides of ΔWXZ are proportional to two sides of ΔXYZ, and

that the included angles between the two sides, ∠WZX and ∠XZY are

congruent, the two triangles, ΔWXZ and ΔXYZ are similar by Side-Angle-

Side, SAS, similarity postulate.

The option that best completes the proof is therefore;

  • \displaystyle \frac{16}{12} = \frac{12}{9} which is; <u>16 over 12 equals 12 over 9</u>

Learn more about the SAS similarity postulate here:

brainly.com/question/11923416

4 0
3 years ago
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