Answer:
y-int = (0, -0.5)
x-int = (-1.2, 0)
Step-by-step explanation:
Hope this helps! :3
plz mark as brainlest!
neither
• Parallel lines have equal slopes
• The product of perpendicular slopes = - 1
the equation of a line in slope-intercept form is
y = mx + c ( m is the slope and c the y-intercept )
y =
x + 3 is in this form
with slope m = 
rearrange 20x + 12y = 12 into this form
subtract 20x from both sides
12y = - 20x + 12 ( divide all terms by 12 )
y = -
+ 1 ← in slope-intercept form
with slope m = - 
Neither of the conditions for parallel/ perpendicular slopes are met
Hence the lines are neither parallel/ perpendicular
Answer:
Their expenses and sales will both equal at 200 ounces.
Step-by-step explanation:
This can be determined using the break-even point in ounce formula as follows:
Break even point in ounce = Fixed cost / Contribution per ounce
Where;
Fixed cost = Advertising = $600
Contribution per ounce = Selling price per ounce - Cost per ounce = $4 - $1 = $3
Substituting the values into equation (1), we have:
Break even point in ounce = $600 / $3 = 200 ounces
Therefore, their expenses and sales will both equal at 200 ounces.
first off let's notice that hmmm the vertex is above the point (3,-3), so if we "assume" is a vertical parabola, then it'd be opening downwards.... anyhow that said, let's plug in those values.
![\bf ~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%5Ctextit%7Bvertical%20parabola%20vertex%20form%7D%20%5C%5C%5C%5C%20y%3Da%28x-%20h%29%5E2%2B%20k%5Cqquad%20%5Cbegin%7Bcases%7D%20%5Cstackrel%7Bvertex%7D%7B%28h%2Ck%29%7D%5C%5C%5C%5C%20%5Cstackrel%7B%22a%22~is~negative%7D%7Bop%20ens~%5Ccap%7D%5Cqquad%20%5Cstackrel%7B%22a%22~is~positive%7D%7Bop%20ens~%5Ccup%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)
![\bf vertex~~(\stackrel{h}{2}~~,~~\stackrel{k}{1})\qquad \implies \qquad y = a(x-2)^2+1 \\\\\\ \stackrel{\textit{we also know that }}{(3~~,~~-3)} \begin{cases} x = 3\\ y = -3 \end{cases}\qquad \implies -3=a(3-2)^2+1 \\\\\\ -3=a(1)^2+1\implies -3=a+1\implies -4=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y = -4(x-2)^2+1~\hfill](https://tex.z-dn.net/?f=%5Cbf%20vertex~~%28%5Cstackrel%7Bh%7D%7B2%7D~~%2C~~%5Cstackrel%7Bk%7D%7B1%7D%29%5Cqquad%20%5Cimplies%20%5Cqquad%20y%20%3D%20a%28x-2%29%5E2%2B1%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bwe%20also%20know%20that%20%7D%7D%7B%283~~%2C~~-3%29%7D%20%5Cbegin%7Bcases%7D%20x%20%3D%203%5C%5C%20y%20%3D%20-3%20%5Cend%7Bcases%7D%5Cqquad%20%5Cimplies%20-3%3Da%283-2%29%5E2%2B1%20%5C%5C%5C%5C%5C%5C%20-3%3Da%281%29%5E2%2B1%5Cimplies%20-3%3Da%2B1%5Cimplies%20-4%3Da%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20y%20%3D%20-4%28x-2%29%5E2%2B1~%5Chfill)
S=3/5, because if we multiply 3 on both sides (to isolate the s), then 1/5 times 3 is 3/5 (and 1/3 times 3 is 1)