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Anna11 [10]
3 years ago
15

What is the greatest common factor or 20 and 24

Mathematics
2 answers:
gogolik [260]3 years ago
8 0

Answer:

The greatest common factor is 4 :)

goblinko [34]3 years ago
3 0
It is 4 :) have a nice day
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Derek is solving the following equation. Find where he made a mistake.
Arisa [49]

Answer:

he was supposed to add three on both sides

4 0
3 years ago
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How many diagonals can be drawn from each vertex of a 15-gon?
tangare [24]

Answer:

Correct option: third one -> 12

Step-by-step explanation:

In a polygon with 'n' vertex, we can trace diagonals from one vertex to all vertices, except to the vertex chosen and the two adjacent vertices (because we would have sides and not diagonals), so we would have 'n - 3' diagonals.

If we have a polygon with 15 vertex, the number of diagonals from one vertex is 15 - 3 = 12.

Correct option: third one

5 0
3 years ago
Which sequence of transformations will only produce a figure similar to but not congruent to the figure ABCD
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A dialation is the answer.
6 0
3 years ago
P(x)= 3x^3-5x^2-14x-4
nexus9112 [7]
   
\displaystyle\\
P(x)=3x^3-5x^2-14x-4\\\\
D_{-4}=\{-4;~-2;~\underline{\bf -1};~1;~2;~4\}\\\\
\text{We observe that } \frac{-1}{3} \text{ is a solution of the equation:}\\
3x^3-5x^2-14x-4=0\\\\


\displaystyle\\
\text{Verification}\\\\
3x^3-5x^2-14x-4=\\\\
=3\times\Big(-\frac{1}{3}\Big)^3-5\times\Big(-\frac{1}{3}\Big)^2-14\times\Big(-\frac{1}{3}\Big)-4=\\\\
=-\frac{1}{9}-\frac{5}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{42}{9}- \frac{4\times 9}{9}=\\\\
 =-\frac{6}{9}+\frac{42}{9}- \frac{36}{9}= \frac{42-6-36}{9}=\frac{42-42}{9}=\frac{0}{9}=0\\\\
\Longrightarrow~~~P(x)~\vdots~\Big(x+ \frac{1}{3}\Big)\\\\
\Longrightarrow~~~P(x)~\vdots~(3x+1)


\displaystyle\\
3x^3-5x^2-14x-4=0\\
~~~~~-5x^2 = x^2 - 6x^2\\
~~~~~-14x =-2x-12x \\
3x^3+x^2 - 6x^2-2x-12x-4=0\\
x^2(3x+1)-2x(3x+1) -4(3x+1)=0\\
(3x+1)(x^2-2x -4)=0\\\\
\text{Solve: } x^2-2x -4=0\\\\
x_{12}= \frac{-b\pm  \sqrt{b^2-4ac}}{2a}=\\\\=\frac{2\pm  \sqrt{4+16}}{2}=\frac{2\pm  \sqrt{20}}{2}=\frac{2\pm  2\sqrt{5}}{2}=1\pm\sqrt{5}\\\\
x_1 =1+\sqrt{5}\\
x_2 =1-\sqrt{5}\\
\Longrightarrow P(x)= 3x^3-5x^2-14x-4 =\boxed{(3x+1)(x-1-\sqrt{5})(x-1+\sqrt{5})}



7 0
3 years ago
Which property of multiplication is shown? 6 · 1 = 1 · 6
saw5 [17]

Answer: Commutative property of multiplication  

Step-by-step explanation: The problem 6 · 1 = 1 · 6 demonstrates the commutative property of multiplication.

In other words, the commutative property of multiplication says that changing the order of the factors does not change the product.  

So for example here, 6 · 1 is equal to 6 and 1 · 6 also equals 6.

Since 6 = 6, we can easily see that 6 · 1 must be equal to 1 · 6.

In more general terms, the commutative property of multiplication can be written as a · b = b · a where <em>a</em> and <em>b</em> are variables that can represent any numbers.

5 0
3 years ago
Read 2 more answers
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