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Sauron [17]
4 years ago
10

Solve 5n=20 math right now please

Mathematics
2 answers:
maksim [4K]4 years ago
8 0

Answer:

n=4

Step-by-step explanation:

slega [8]4 years ago
7 0

Answer:

n=4

Step-by-step explanation:

5x4=20

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What is the equation of a line that passes through point r(−3, 5) and has a slope of 4?
nexus9112 [7]
The equation of any line is:
y=mx+b  m is slope.

We just need to put inside of equation x=(-3) and y=5:
5=4*(-3)+b
17=b

It follows that equation of a line is:
y=4x+17
4 0
4 years ago
Can someone like an ace or very good at math help me
eimsori [14]
Supplementary angles , when added, = 180
complimentary angles, when added, = 90

< AQC + < GQC = 180.....supplementary
< BQD + < DQE = 90.......complimentary
< CQE + < EQF = 90.......complimentary
< GQF , < FQE.....neither
< BQC + < DQC = 90....complimentary

< W and < X are supplementary...
if < W = 37, then < X = (180 - 37) = 143

< S and < T are complimentary
if < S = 64, then < T = (90 - 64) = 26

< C and < D are supplementary
if < C = 83, the < D = (180 - 83) = 97

cant read all of the last one.....but if they are complimentary, and 
< U = 41, then the other angle is : (90 - 41) = 49


4 0
4 years ago
7070
SVETLANKA909090 [29]

Answer:

do you want the answer because i am telling your teacher that you are cheating

Step-by-step explanation:

8 0
3 years ago
How do you find measure a and c
astra-53 [7]
You can use the measure of 112 on the similar shape to find b, as they are same side exterior angles. From there, you can find both a and c, because a/b and b/c are supplementary angles. 

a = 68 degrees

c = 68 degrees
5 0
3 years ago
Read 2 more answers
The diagram shows a sector of a circle radius 10cm
Yuki888 [10]

Answer:

\text{Perimeter of sector = 43.6 (Rounded to the nearest tenth.)}

Step-by-step explanation:

\text{Perimeter of the sector = Radius + arc length + radius}

\text{Radius = 10 cm}

\text{Perimeter of the sector = 10 + arc length + 10  }

 \text{Perimeter of the sector = 20 + arc length  }

\text{arc length   = (sector angle/ 360 ) * perimeter of the circle}

\text{Perimeter of a circle }=2\pi r

\text{sector angle} = 135

\text{arc length}   =  (135/ 360 ) * 2\pi (10)

= (3/8) 20\pi

= 15\pi /2

\text{Using  }\pi =3.14

= 15 * 3.14 /2

= 23.55

\text{Perimeter of the sector = 20  + 23.55}

= 43.55

= 43.6  cm

\text{perimeter of the sector  = 43.6  cm }

8 0
2 years ago
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