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4 years ago

Solve 5n=20 math right now please

Mathematics

2 answers:

maksim [4K]4 years ago

8 0

Answer:

n=4

Step-by-step explanation:

slega [8]4 years ago

7 0

Answer:

n=4

Step-by-step explanation:

5x4=20

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-(4y) to the second power of y= -3

andrezito [222]

144
-(4x-3)^2
-(-12)^2
12^2 =12x12=144

5 0

3 years ago

What times what times what equals 121

defon

Answer:

11x11=121

Step-by-step explanation:

121 is equal to 11 times 11.

3 0

3 years ago

Simone paid $13 for an initial year's subscription to a magazine. The renewal rate is $8 per year. This situation can be represe

elixir [45]

Data Input

Simone paid $13 for an initial year's

The renewal rate is $8 per year

Equation

y = 8x + 13

Table

x (number of years renewed) | (total cost in dollars)

0 -> 13 dollars

1 -> 21 dollars

2 -> 29 dollars

3 -> 37 dollars

4 -> 45 dollars

7 0

2 years ago

Rutherfordium- 265 is a radioactive substance that has a half-life of 13 hours. If there is a 149g sample of Rutherfordium- 265

Anna [14]

Answer:

3.21 grams

Step-by-step explanation:

First we are finding the radioactive decay constant using the formula:

lambda = $\frac{ln(2)}{half-life}$

where

lambda is the radioactive decay constant.

$half-life$ is the half life of the radioactive substance.

We know from our problem that Rutherfordium- 265 has a half-life of 13 hours, so let's replace the value in our formula.

lambda = $\frac{ln(2)}{13hours}$

lambda = 0.0533 per hour

Now we can use the decay formula to find the remaining quantity of the substance:

$N_t=N_0e^{(-lamda)(t)$

where

$N_t$ is the ending amount

$N_0$ is the beginning amount

$t$ is the time (in hours)

We know from our problem that there is a 149g sample of Rutherfordium- 265 left at 12am on October 19th, so $N_0=149$ . Notice that there are exactly 3 days from 12 am October 19th to 12 am October 22nd, so we have $3days(\frac{24hours}{1day} )=72hours$ ; therefore $t=72$ . Now we can replace all the values in our formula: