Step-by-step explanation:
Let the speed of the plane in still air = x
and speed of wind = y
Now from city A to B
dIstance = speed × time
732732 = (x - y) × 2 (1)
From city B to A
Distance = speed × time
732732 = (x + y) × 1.5 (2)
From (1) and (2)
2x - 2y = 1.5x + 1.5y
0.5x = 3.5y
x = 7y
If we plug in (1)
732732 = (7y - y) × 2
732732/12 = 12y/12
y = 61061
Since x = 7y
= 427427 miles/hr
Speed of still air plane is 427427 miles/hr
Speed of wind = 61061miles/hr
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x= 5
12 squared + b squared = 13 squared
144+ b squared = 169
b squared = 25
b squared= √25
b=5
Answer:
1 / q^30.
Step-by-step explanation:
[(p^2)(q^5)]^-4 * [(p^-4)(q^5)]^-2
Using the law (a^b)^c = a^bc :-
= p^-8 * q^-20 * p^8 * q^-10
= p^(-8+8) * q^(-20-10)
= p^0 * q^-30
= 1 * q^-30.
= 1 / q^30.