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3 years ago

Please help me!!!!!!!!!!!!!!!

Mathematics

1 answer:

Ainat [17]3 years ago

7 0

r = 7.53 so d = 2r = 2(7.53) = 15.06 cm

Area of square = d^2 / 2 = (15.06)^2 / 2 = 113.41 cm^2

Area of circle = 3.14 (7.53)^2 = 178.04 cm^2

Area of yellow region = Area of circle - Area of square

Area of yellow region = 178.04 cm^2 - 113.41 cm^2

Area of yellow region =64.63 cm^2 = 64.6 cm^2 (nearest tenth)

Answer

64.6 cm^2

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2 years ago

PLZ HELP WITH THIS QUESTION PLZ CORRECT ANSWERS!!! LOVE YOU THNX

iogann1982 [59]

Answer:

1) The value of x= 0.0642

2) $sin\theta=\frac{P}{H}=\frac{24}{25}$

$cos\theta=\frac{B}{H}=\frac{7}{25}$

$tan\theta=\frac{P}{B}=\frac{24}{7}$

$cosec\theta=\frac{H}{P}=\frac{25}{24}$

$cot\theta=\frac{B}{P}=\frac{7}{25}$

Step-by-step explanation:

1) Given : A right angle triangle with sides x and 10 and angle is 50°

To find : Value of x

Solution : Since, it is a right angle triangle

Therefore, we apply $cos\theta=\frac{B}{H}$

Where Base = x, Hypotenuse= 10, angle = 50°

$cos(50)=\frac{x}{10}$

$0.642=\frac{x}{10}$

$0.0642=x$

The value of x= 0.0642

2) Given : $sec\theta=\frac{25}{7}$

To find : Value of $sin\theta,cos\theta,tan\theta,cosec\theta,cot\theta$

Solution : We have given $sec\theta=\frac{25}{7}$

$sec\theta=\frac{H}{B}$

so, B= 7 , H=25

By Pythagoras theorem,

$H^2=P^2+B^2$

$25^2=P^2+7^2$

$625-49=P^2$

$\sqrt{576}=P^2$

$P=24$

Now, P=24, B=7, H=25

$sin\theta=\frac{P}{H}=\frac{24}{25}$

$cos\theta=\frac{B}{H}=\frac{7}{25}$

$tan\theta=\frac{P}{B}=\frac{24}{7}$

$cosec\theta=\frac{H}{P}=\frac{25}{24}$

$cot\theta=\frac{B}{P}=\frac{7}{25}$

5 0

3 years ago