3 years ago

Complete the square to find the standard form for this circle: x^2 + 4x + y^2 + 16y - 20 = 0

1 answer:

atroni [7]3 years ago

6 0

Step-by-step explanation:

x² + 4x + y² + 16y - 20 = 0

(x² + 4x + 4) + (y² + 16y + 64) - 4 - 64 - 20 = 0

(x + 2)² + (y + 8)² = 88.

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Complete the square to find the standard form for this circle: x^2 + 4x + y^2 + 16y - 20 = 0​