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PilotLPTM [1.2K]
3 years ago
8

What is the 3rd term of the sequence? a1 = 40 and an = 0.5(an – 1) a3 =

Mathematics
1 answer:
777dan777 [17]3 years ago
8 0
\bf \begin{array}{llll}
term&value\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
a_1&40\\\\
a_2&0.5(a_{n-1})\\
&0.5(a_{2-1})\\
&0.5(a_1)\\
&0.5(40)\\
&20\\\\
a_3&0.5(a_{3-1})\\
&0.5(a_2)\\
&0.5(20)
\end{array}
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Answer:

21-6=15

Step-by-step explanation:

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If x =5 find the value of 2x squared
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Step-by-step explanation:

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Solve.<br> log 3 + log x - log(x + 1) = log 2<br> Please please help
weqwewe [10]

Answer:

x = 2

Step-by-step explanation:

Given the equation as;

log 3 + log x - log(x + 1) = log 2

collect like terms

log x - log(x + 1) = log 2-1og 3

Re-write the equation by applying laws of logarithms in that when you subtract logs you divide the numbers/terms. This will give

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Cancel log on both sides to remain with;

x/ x+1 = 2/3

Apply cross-product

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8 0
3 years ago
Determine the digits of Y from these clues.
Doss [256]

Answer:

Y = 963

Step-by-step explanation:

The digits of Y add to 18.  The first digit is 3 times the third digit.  The second  digit is 2 times the third digit.  Y is a three digit number.​

Let Y a three digit number be: abc

First digit = a , Second digit = b, Third digit = c

Also given,

The digits of Y add to 18. => a+b+c = 18     eq(i)

The first digit is 3 times the third digit. => a = 3c     eq(ii)

The second digit is 2 times the third digit. => b = 2c     eq(iii)

Putting value of a and b in eq(i)

3c + 2c + c = 18

6c = 18

c= 18/6

c = 3

Putting value of c in eq(ii) and eq(iii)

a= 3c => a=3(3) => a= 9

b= 2c => b=2(3) => b = 6

Thus, Y = abc

Y = 963

8 0
3 years ago
$3500 bottle over five years with an interest rate of 4% is how much interest ?and what is the total value?
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3 years ago
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