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kirza4 [7]
3 years ago
14

Help on number 3!!!

Mathematics
1 answer:
DaniilM [7]3 years ago
5 0

Answer:i had same problem i need help too.

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Evaluate this expression 5•10^2+3<br><br> A.) 2503<br><br> B.) 103<br><br> C.) 503<br><br> D.) 300
qwelly [4]

Answer:

503 or C

Step-by-step explanation:

10^2= 10 X 10 = 100

100 x 5 = 500

500 + 3 =503

8 0
3 years ago
Read 2 more answers
Find the interval in which the function is negative.
DedPeter [7]

Answer:

  B. II only . . . (-1, 4)

Step-by-step explanation:

The function factors as ...

  f(x) = (x +1)(x -4)

The factors are zero when x=-1 and x=4. The value of the function will be negative when one of these factors is negative, between x=-1 and x=4. In interval notation, that interval is ...

  (-1, 4) . . . interval for f(x) < 0 . . . . . . interval description II (only)

3 0
3 years ago
2. Convert 61.13° to degrees, minutes, and seconds. (2 points)
Evgesh-ka [11]
The answer is the first option.

4 0
3 years ago
30)
masya89 [10]

Answer:

871.5

Step-by-step explanation:

directly proportional

y = kx

y = 12 when x = 14

12 = k(14)

k = 12/14

k = 6/7

--------------------------

what is the value of x when y = 747

747 = (6/7) * x

Multiply both sides by 7/6

747 * 7/6 = x

871.5 = x

6 0
3 years ago
For what value of k, if any, will y = ksin (5x) + 2cos (4x) be a solution to the differential equation y'' +16y =-27sin(5x)?
emmainna [20.7K]

Answer:

c. 3

Step-by-step explanation:

y = k sin(5x) + 2 cos(4x)

y' = 5k cos(5x) − 8 sin(4x)

y" = -25k sin(5x) − 32 cos(4x)

y'' + 16y = -27 sin(5x)

(-25k sin(5x) − 32 cos(4x)) + 16(k sin(5x) + 2 cos(4x)) = -27 sin(5x)

-25k sin(5x) − 32 cos(4x) + 16k sin(5x) + 32 cos(4x) = -27 sin(5x)

-9k sin(5x) = -27 sin(5x)

k = 3

4 0
4 years ago
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