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2 years ago

Use the box-and-whisker plots to determine which statements are true.

Mathematics

1 answer:

Anastasy [175]2 years ago

8 0

The true statements are :

the average monthly temperatures of New Orleans are not as varied as that of Indianapolis.

The median of the average monthly temperatures of New Orleans is equal to the upper quartile of the average monthly temperature of Indianapolis.

<h3>What are the true options?</h3>

A box plot is used to study the distribution and level of a set of scores. The box plot consists whiskers and a box. The whiskers represents the minimum and maximum scores. The difference between the minimum and maximum scores is the range.

On the box, the first line to the left represents the lower quartile. The next line on the box represents the median. The third line on the box represents the upper quartile.

Range for New Orleans = 85 - 50 = 35

Range for Indianapolis = 75 - 25 = 50

Median for New Orleans = 70

Upper quartile for Indianapolis = 70

To learn more about box plots, please check: brainly.com/question/27215146

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riadik2000 [5.3K]

Answer:

Step-by-step explanation:

p - 13 = 29

Add 13 to both sides.

p - 13 + 13 = 29 + 13

p = 42

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3 years ago

A baseball player hits a ball at an angle of 52 degrees and at a height of 4.5 ft. if the ball's initial velocity after being hi

Dafna1 [17]

Answer:

$t\approx 5.865\,s$

Step-by-step explanation:

The motion equations that describe the ball are, respectively:

$x = \left[\left(152\,\frac{ft}{s} \right)\cdot \cos 52^{\circ} \right] \cdot t$

$y = 4.5\,ft + \left[\left(152\,\frac{ft}{s} \right)\cdot \sin 52^{\circ} \right] \cdot t - \frac{1}{2}\cdot \left(32.174\,\frac{ft}{s^{2}} \right) \cdot t^{2}$

The time required for the ball to hit the ground is computed from the second equation. That is to say:

$4.5\,ft + \left[\left(152\,\frac{ft}{s} \right)\cdot \sin 52^{\circ} \right] \cdot t - \frac{1}{2}\cdot \left(32.174\,\frac{m}{s^{2}} \right) \cdot t^{2} = 0$

Given that formula is a second-order polynomial, the roots of the equation are described below:

$t_{1}\approx 5.865\,s$ and $t_{2} \approx -0.048\,s$

Just the first root offers a realistic solution. Then, $t\approx 5.865\,s$ .

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3 years ago

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2 years ago

If the measure of angle ABF=6x+26 and the measure of angle EBF=2x9 and measure of angle ABE= 11x-31 find the measure of angle AB

Hunter-Best [27]

Its not clearly given that whether EBF = 2x + 9 or 2x - 9.

I have written the solution for both.

If EBF = 2x + 9,

then ABF = 6x + 26 and ABE = 11x - 31.

Now, ABE = ABF + EBF

11x - 31 = (6x + 26) + (2x + 9)

= (6x + 2x) + (26 + 9)

= 8x + 35

11x - 8x = 35 + 31

3x = 66

x = 22

Therefore, ABF = 6x + 26 = 6(22) + 26 = 132 + 26 = 158°

If EBF = 2x - 9,

then ABF = 6x + 26 and ABE = 11x - 31.

Now, ABE = ABF + EBF

11x - 31 = (6x + 26) + (2x - 9)

= (6x + 2x) + (26 - 9)

= 8x + 17

11x - 8x = 17 + 31

3x = 48

x = 16

Therefore, ABF = 6x + 26 = 6(16) + 26 = 96 + 26 = 122°

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3 years ago