Since we can't have a 0 in the denominator,
Also, in the graph ...you can see that the function approaches x=5 but never actually reaches it.
∴The value of x that don't lie in the domain of the function is
5
One hundred and three tens
My answer would be a. a radio play is<span> the art of performing stories, acts, or even full-lengths musicals to be broadcast on radios. so baiscly u can really see them at all.</span>
Answer: P(T|B) = 2/3= 0.667
Step-by-step explanation:
Given;
Probability that there is free breakfast at work
P(B) = 0.25
Probability that your coworker lied
P(L) = (1/3)
Probability that your coworker did not lie
P(T) = 1-1/3 = 2/3
Since your coworker already told you there is free breakfast, the condition probability now depends solely on whether he lied or not.
P(T|B) = P(B)P(T)/[P(B)P(T) + P(B)P(L)]
P(T|B) = (0.25×2/3)/[(0.25×2/3 + (0.25×1/3)]
P(T|B) = 2/3= 0.667
Hint: since the coworker already confirmed that there is free breakfast, the probability that there will be free breakfast now depends solely on the whether the co-workers said the truth, which have a probability of 2/3.
i.e P(T|B) = P(T) = 2/3
Answer:
(a) The mean and standard deviation of the pallet weight are 3000 lb and 10.95 lb respectively.
(b) The probability that the pallet weight (W) will exceed 3015 lb is 0.085.
Step-by-step explanation:
Let the random variable <em>X</em> denote the weight of the parts.
The random variable <em>X</em> is normally distributed with parameters, <em>μ</em> = 1 lb and <em>σ</em> = 0.20 lb.
It is provided that a shipping pallet holds 10 boxes and each box holds 300 parts of different types.
That is, there are a total of 300 × 10 = 3000 parts in a pallet.
(a)
Compute the mean and standard deviation of the pallet weight as follows:
Mean of the pallet weight = n × E (X)
Standard deviation of the pallet weight =
Thus, the mean and standard deviation of the pallet weight are 3000 lb and 10.95 lb respectively.
(b)
Compute the probability that the pallet weight (W) will exceed 3015 lb as follows:
*Use a <em>z</em>-table.
Thus, the probability that the pallet weight (W) will exceed 3015 lb is 0.085.