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Illusion [34]
3 years ago
8

The half-life of a radioactive isotope is the time it takes for a quantity of the isotope to be reduced to half its initial mass

. Starting with 125 grams of a radioactive isotope, how much will be left after 5 half-lives? Use the calculator provided and round your answer to the nearest gram.
Mathematics
1 answer:
krok68 [10]3 years ago
7 0
So, 0.5^5 is 0.03125
multiply that by 125 and get your answer.
*3.90625* (4)
just saying, I got the 0.5^5 thing because 5 is the number of half-lives (x) and 0.5 is the rate of loss (or whatever its called).
If it were to gain, you would put 1.5

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State the name of the property illustrated. (x + 7) + [-(x + 7)] = 0
Vadim26 [7]

Answer:

addittional property

Step-by-step explanation:

3 0
2 years ago
£880 is divided between Jim, Krutika & Natasha so that Jim gets twice as much as Krutika, and Krutika gets three times as mu
krok68 [10]

Answer:

264 pounds

Step-by-step explanation:

Write the question in the form of a ratio:

Natasha: Krutika: Jim

1:3:6

Now, we divide the amount of 880 in the ratio.

there are 10 parts in total.

1 part = 880 divided by 10 = 88.

since Krutika gets 3 parts, she gets 88 x 3 = 264

7 0
3 years ago
A system of equations is shown below: Equation A: 4c = d − 8 Equation B: c = 5d + 8 Which of the following steps should be perfo
Alchen [17]
<span>Equation A: 4c = d − 8
</span><span>Equation B: c = 5d + 8 
</span>
Multiply Equation A by -5:
Equation A: - 20c = -5d + 40

Equation (1) + (2) :
-19c = 48

Answer: <span>B. Multiply equation A by -5</span>
3 0
3 years ago
This is algebra.. and I am rea bad at it
katovenus [111]
^^^ this is correct, but bro it’s just simple subtraction. Use a calculator or sum
5 0
3 years ago
A student wanted to construct a 95% confidence interval for the average age of students in her statistics class. She randomly se
Darina [25.2K]

Answer: (17.42, 20.78)

Step-by-step explanation:

As per given , we have

Sample size : n= 9

\overline{x}=19.1 years

Population standard deviation is not given , so it follows t-distribution.

Sample standard deviation : s= 1.5 years

Confidence level : 99% or 0.99

Significance level : \alpha= 1-0.99=0.01

Degree of freedom : df= 8  (∵df =n-1)

Critical value : t_c=t_{(\alpha/2,\ df)}=t_{0.005,\ 8}= 3.355

The 99% confidence interval for the population mean would be :-

\overline{x}\pm t_c\dfrac{s}{\sqrt{n}}

19.1\pm (3.355)\dfrac{1.5}{\sqrt{ 9}}\\\\=19.1\pm1.6775\\\\=(19.1-1.6775,\ 19.1+1.6775)\\\\=(17.4225,\ 20.7775)\approx(17.42,\ 20.78)

Hence, the 99% confidence interval for the population mean is (17.42, 20.78) .

7 0
3 years ago
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