Question

Plzz solve this easy calculus :')

Answer 1

Answer:

$\sin \: x - \cos x \: + c$

Step-by-step explanation:

$\int \frac{cos2x}{ \sqrt{1 - sin2x} } dx \\ \\ = \int \frac{ {cos}^{2}x - {sin}^{2}x } { \sqrt{ {sin}^{2}x + {cos}^{2}x - 2sinx \: cosx } } dx \\ \\ = \int \frac{ ({cos}x - {sin}x )({cos}x + {sin}x )} { \sqrt{ {({cos}x - {sin}x )}^{2} } } dx \\ \\ = \int \frac{ ({cos}x - {sin}x )({cos}x + {sin}x )} {{ {({cos}x - {sin}x )} } } dx \\ \\ = \int({cos}x + {sin}x)dx \\ \\ = \int{cos}x \: dx + \int{sin}x \: dx \\ \\ = \sin \: x - \cos x \: + c$