Answer:
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = 0.0087
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the mean of the Population = 95
Given that the standard deviation of the Population = 5
Let 'X' be the random variable in a normal distribution
Let X⁻ = 96.3
Given that the size 'n' = 84 monitors
<u><em>Step(ii):-</em></u>
<u><em>The Empirical rule</em></u>


Z = 2.383
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = P(Z≥2.383)
= 1- P( Z<2.383)
= 1-( 0.5 -+A(2.38))
= 0.5 - A(2.38)
= 0.5 -0.4913
= 0.0087
<u><em>Final answer:-</em></u>
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = 0.0087
<h2>
Height of tree is 7.5 feet</h2>
Step-by-step explanation:
Let t be the height of pole.
Given that the tree is 5 feet shorter than a pole.
Height of pole = t + 15
Also given that the pole is 3 times as tall as the tree.
Height of pole = 3t
So we have
t + 15 = 3t
2t = 15
t = 7.5 feet
Height of tree = 7.5 feet
45
1. Area = 1/2 B(base) x H(height)
2. Area = 1/2 9 x 10
3. Area = 1/2 90
4. Area = 45 inches
Start at negative 5 since that’s your y-intercept.
Since 3/5 is your slope and slope equals rise over run you go up 3 units and go right 5 units.
We want to know how many 1/8's are in 3/4, so we divide.

Flip the 2nd fraction and multiply:

Multiply the numerators and denominators together:

Divide: