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3 years ago

Find the area of the shaded region. Round to the nearest hundredth where

Mathematics

1 answer:

Svetllana [295]3 years ago

6 0

Answer:

192.42m²

Step-by-step explanation:

The larger circle: pi(10.5²)≈346.36

The smaller circle: pi(7²)≈153.94

Then subtract

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Given x=5 + √16 , select the value(s) of x. -11 1 9 21

Schach [20]

Answer:

The answers would be 9 and 1.

Step-by-step explanation:

x= 5±√16 can be separated into two equations.

x=5+√16 and x=5-√16

1. 5+√16 can be solved by simplify √16, which is 4. So then it would become 5+4 which equals 9.

2. 5-√16 can be solved by simplifying √16 which is 4. So then it would become 5-4 which equals 1.

So the values of x are 9 and 1.

6 0

3 years ago

Read 2 more answers

A rectangle has a width of 12 ft and a length of 4 ft.

polet [3.4K]

It's A, increased by a factor of 6.

8 0

3 years ago

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Find limit as x approaches two of quantity x squared minus four divided by quantity x minus two. You must show your work or expl

Brut [27]

Answer:

Step-by-step explanation:

lim (x^2 - 4) / (x - 2)

x --> 2

When we plug x =2, we get

(2^2 - 4) / (2 - 2)

= (4 - 4)/(2 - 2)

= 0 /0

Which is undefined.

Now we have to use L'hospital rule. Which says we need to differentiate the numerator and the denominator and apply the limit.

When we differentiate x^2 -4, we get 2x

When we differentiate x -2, we get 1

lim 2x/1

x --> 2

Now apply, the limit x = 2

2(2)/1

= 4/1

= 4

Therefore, limit of this function is 4, when x tends to 2.

Hope you will understand the concept.

Thank you.

3 0

3 years ago

Read 2 more answers

A silo is constructed using a cylinder with a hemisphere on top. The circumference of the hemisphere and the circumference of th

givi [52]

1. The surface that will be exposed to the rain is the lateral surface of the cylinder and the hemisphere.

2. The lateral area of the cylinder is a rectangle with height equal to the height of the cylinder and width equal to the circumference of the base of the cylinder.

3. the circumference of the base = 2 $\pi$ r=2* $\pi$ *5=10 $\pi$
so the lateral area = 10 $\pi$ *h=10 $\pi$ *40=400 $\pi$ ( $ft^{2}$ )

4. The surface area of a sphere is $4 \pi r^{2}$
so the surface of the hemisphere = $\frac{1}{2} *4 \pi r^{2}=2 \pi (5)^{2}=50 \pi$ ( $ft^{2}$ )

5. Total area exposed = 450 $\pi$ $ft^{2}$

4 0

3 years ago

Read 2 more answers

If f(x)= 2a|3x – 9| – ax, where a is some constant not equal to zero, find f ′(3).

sineoko [7]

Hmm, it actually doesn't exist because at x=3, that is where the absoluve value turns into 0. the graph has a point at x=3 and there is no slope of a pointy part of a function. I mean the slope is undinfed, it is DNE

8 0

3 years ago