Answer: the shaded region = 69.66mm^2
Explanation:
Assume shaded region is X
Then :
X + Area of circle = area of square
X = area of square - area of circle
Find area of square:
Side length = 18mm
Area = 18 x 18 = 324
Find area of circle:
Side length of a square = the diameter of the circle = 18mm
And r(radius) = d/2 = 18/2 = 9
Area = pi x 9^2 = 254.34
Now find X
X = 324 - 254.34 = 69.66
Answer: 5y + x
Step-by-step explanation: As you first step to this problem, change all your minus signs to plus negatives.
To simplify, we can only combine what are called our like terms and in this problem, we have one y-term and we have a pair of like terms in our x-terms.
So let's start by combining our y-terms.
13y + -7y simplifies to 5y.
Now we have one x-term so we have 5y + x.
Answer:
1
Step-by-step explanation:
s he crossed toward the pharmacy at the corner he involuntarily turned his head because of a burst of light that had ricocheted from his temple, and saw, with that quick smile with which we greet a rainbow or a rose, a blindingly white parallelogram of sky being unloaded from the van—a dresser with mirrors across which, as across a cinema screen, passed a flawlessly clear reflection of boughs sliding and swaying not arboreally, but with a human vacillation, prod
themselves, Akakiy Akakievitch indulged in no kind of diversion.”
Yeah, I love sentences too. That’s why I created this online course in how to write a better sentence.
Answer:
(a) 218.6 N
(b) 97.14 N
Step-by-step explanation:
When the system is in equilibrium, the net torque on the system is zero.
AC = 1.5 m, CD = 2.3 m, DB = 5 - 1.5 - 2.3 = 1.2 m
Let the centre of gravity of plank is at G.
AG = 2.5 m, CG = 2.5 - 1.5 = 1 m, GB = 2.5 m
(a) Let the reaction at C is R and at D is R'.
R + R' = 29 x 9.8 = 284.2 N ... (1)
Take the torque about C.
29 x 9.8 x CG = R' x GD
29 x 9.8 x 1 = R' x 1.3
R' = 218.6 N
(b) Take the torque about D.
6 x 9.8 x AD = R x CD
6 x 9.8 x (1.5 + 2.3) = R x 2.3
R = 97.14 N
I’m so sorry I need points but I’m gonna manifest that someone smarter will see this and answer