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2 years ago

The area of a city is commonly measured in

Mathematics

2 answers:

ratelena [41]2 years ago

8 0

The answer is B) square miles. This is because a city is very big, and the measure it, miles would be ideal.

WARRIOR [948]2 years ago

3 0

B) square miles because as mentioned above a city is usually large it could be miles.

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Please answer this quickly! Thank you!

Morgarella [4.7K]

Answer:

i think 3/5 but not 100%

Step-by-step explanation:

sorry if im wrong

8 0

2 years ago

I need help, can someone please explain this step by step.

Helga [31]

180-117.3=62.7

answer is 62.7

3 0

2 years ago

I need help with this

olga2289 [7]

Answer:

x = 24.52

Step-by-step explanation:

Since this is a right triangle, use Pythagorean Theorem to solve for the hypotenuse.

Pythagorean Theorem: a² + b² = c²

24² + 5² = x²

576 + 25 = x²

601 = x²

√601 = x

4 0

2 years ago

ONLY 2 MINS HELP!!!!!!!!!!!!!!!!!!!1

Tresset [83]

Answer:

the answer you are looking for is C

7 0

2 years ago

A public health official is planning for the supplyof influenza vaccine needed for the upcoming flu season. She wants to estimat

Marizza181 [45]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.04}{1.64})^2}=420.25$

And rounded up we have that n=421

Step-by-step explanation:

We know that the sample proportion have the following distribution:

$\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by $\alpha=1-0.90=0.1$ and $\alpha/2 =0.05$ . And the critical value would be given by:

$z_{\alpha/2}=-1.64, z_{1-\alpha/2}=1.64$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.04$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

We assume that a prior estimation for p would be $\hat p =0.5$ since we don't have any other info provided. And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.04}{1.64})^2}=420.25$

And rounded up we have that n=421

5 0

3 years ago