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3 years ago

Can someone give me a word problem for dividing these two fractions: 6 and 1/3

Mathematics

2 answers:

Alika [10]3 years ago

7 0

Answer: 18

Step-by-step explanation:

Ilya [14]3 years ago

5 0

Jake has 6 friends he needs to make cookies for he needs 1/3 of chocolate chips

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Is this statement true or false? *<br> If an odd number is less<br> than 15, then it is prime.

Hatshy [7]

Answer: That is false

Step-by-step explanation: 9 is odd but not prime

8 0

3 years ago

50 points help (show ur work)<br> Answer all of them

salantis [7]

Answer:

5. $40

6. 500 students

7. 60 books

8. 63 pages

Step-by-step explanation:

<h3><u>Question 5</u></h3>

Given:

Aiden spent $18 on souvenirs.
$18 is 45% of the money he brought on the trip.

Let x be the money Aiden brought on the trip.

Create equivalent ratios with the given information and defined variable, and <u>solve for x</u>:

$\implies 18:45\%=x:100\%$

$\implies 18:0.45=x:1$

$\implies \dfrac{18}{0.45}=\dfrac{x}{1}$

$\implies 18=0.45x$

$\implies x=\dfrac{18}{0.45}$

$\implies 40$

Therefore, Aiden brought $40 on the trip.

<h3><u>Question 6</u></h3>

Given:

Angel received 300 votes.
300 votes was 60% of all the votes.

Let x be the number of students who voted in the election.

Create equivalent ratios with the given information and defined variable, and <u>solve for x</u>:

$\implies 300:60\%=x:100\%$

$\implies 300:0.6=x:1$

$\implies \dfrac{300}{0.6}=\dfrac{x}{1}$

$\implies 300=0.6x$

$\implies x=\dfrac{300}{0.6}$

$\implies x = 500$

Therefore, there were 500 students who voted in the election.

<h3><u>Question 7</u></h3>

Given:

The students sold 80% of the books.
The total number of books they sold is 48.

Let x be the number of books in the sale.

Create equivalent ratios with the given information and defined variable, and <u>solve for x</u>:

$\implies 80\%:48=100\%:x$

$\implies 0.8:48=1:x$

$\implies \dfrac{0.8}{48}=\dfrac{1}{x}$

$\implies 0.8x=48$

$\implies x=\dfrac{48}{0.8}$

$\implies x=60$

Therefore, there were 60 books in the book sale.

<h3><u>Question 8</u></h3>

Given:

Aiyana read 147 pages of the book.
She completed 70% of the book.

If she has completed 70% of the book, then she still has 30% left to read, as 100% - 70% = 30%.

Let x be the number of pages Aiyana still has to read.

Create equivalent ratios with the given information and defined variable, and <u>solve for x</u>:

$\implies 70\%:147=30\%:x$

$\implies 0.7:147=0.3:x$

$\implies \dfrac{0.7}{147}=\dfrac{0.3}{x}$

$\implies 0.7x=44.1$

$\implies x=\dfrac{44.1}{0.7}$

$\implies x=63$

Therefore, Aiyana still has 63 pages left to read.

5 0

1 year ago

Kayla has $45 and wants to buy three shirts that are originally priced at $18 each. They are on sale for 20% off. After applying

tester [92]

Answer: No, as the total cost of the 3 shirts w/ sales tax is $45.36 and she only has $45.

Step-by-step explanation:

Start by finding the price of one shirt on sale.

$18*0.2$

This equals 3.6 which is how much will be deducted from the original price.

One shirt costs $18-3.6\\$ when its 20% off.

This is equal to $14.40.

Since she wants to buy 3 of them we just multiply the $14.40 by 3.

$14.4*3=\\$

This equals $43.2 but this is without a 5% sales tax which is normally added to the total end price.

To add a sales tax you take the sales tax percent plus 1 and multiply it to the $43.2.

$43.2*1.05=\\$

This means the total price of Kayla's purchase will be $45.36.

This is over her $45 she has so she can not buy it.

6 0

3 years ago

Of the 645 students in the freshman class, 85 are left-handed. About what percentage of the students are left-handed? Round to t

jeka57 [31]

Answer:

About 13% of the freshman class are left-handed

Step-by-step explanation:

To find the percentage of a whole you need to divide the part by the whole number (85/645 = 0.1316), then you round to the nearest tenth (0.13) and change it into a percentage by moving the decimal point 2 numbers to the right. (13%)

4 0

3 years ago

How do i find if the figures are similar

VikaD [51]

The picture you attached is too fuzzy to read.

But in general, two figures are similar if each angle in one of them
is equal to the corresponding angle in the other one.

6 0

3 years ago