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egoroff_w [7]
2 years ago
14

8th Grade Math, Helppppppppp Now Plsssssss! What is the function of the nucleus in plant and animal cells? A. Produces all the p

ower of the cell B. Creates proteins within the cell C. Control all cells activity, contains DNA D. Allows things in an out of the cell
Mathematics
2 answers:
Nookie1986 [14]2 years ago
4 0

Answer:

science budo but nucleus controls cell activity and contains dna

Umnica [9.8K]2 years ago
3 0

Answer:

C. Control all cells activity, contains DNA

Step-by-step explanation:

The nucleolus makes ribosomal subunits from proteins and ribosomal RNA, also known as rRNA. It then sends the subunits out to the rest of the cell where they combine into complete ribosomes.

Also.... that's not math.

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Janna works at a lab with a huge circular particle accelerator. It has a radius of 4 kilometers. What is the accelerator's diame
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Step-by-step explanation:

since it is a circle the diameter is two times larger than radius.So 4×2=8km

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05.01 MC)
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Step-by-step explanation:

y + 2 = -3(x - 0)

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2 years ago
1. A buoy floats 19 yards from the eastern most point of a boat and 15 yards from the western most point of a second boat. The a
Black_prince [1.1K]

The laws of cosines and law of sines can be used given that two sides

and an included angle, or two angles a side are known.

Response:

1. The other angles in the triangle formed by the buoy are approximately;

  • <u>31.1° and 40.9°</u>

2. Distance of the helicopter from the first island is approximately;

  • <u>14.5 miles</u>

<h3>How is the Law of Sines and Cosines used?</h3>

Given parameters are;

Distance of the buoy from the easternmost point of a boat = 19 yards

Distance of the buoy from the westernmost point of the other boat = 15 yards

Angle formed from the buoy to the two boats = 108°

Distance between the two boats, <em>d</em>, is given by the law of cosines, as follows;

d² = 19² + 15² - 2 × 19 × 15 × cos(108°) = 586 - 570·cos(108°)

d = √(586 - 570·cos(108°))

By the law of Sines, we have;

\dfrac{d}{sin(108^{\circ})} = \mathbf{\dfrac{15}{sin(Angle \ formed \ from \ the \ boat \ on \ the \ West, \ \theta_1)}}

Which gives;

sin(\theta_1) = \mathbf{ \dfrac{15 \times sin(108^{\circ})}{\sqrt{586 - 570 \cdot cos(108^{\circ})} }}

The o

\theta_1 = arcsin \left( \dfrac{15 \times sin(108^{\circ})}{\sqrt{586 - 570 \cdot cos(108^{\circ})} } \right) \approx   \mathbf{31.1^{\circ}}

The other angles formed in the triangle containing the buoy are;

  • θ₁ ≈ <u>31.1</u>
  • θ₂ ≈ 180° - 108° - 31.1° ≈<u> 40.9°</u>

2. Distance between the two islands = 20 miles

Angle of elevation with one island = 15°

Angle of elevation with the second island = 35°

Required:

The mileage (distance travelled) of the helicopter.

Solution:

Let <em>A</em> represent the island that has an angle of elevation to the helicopter

of 15°, and let <em>B</em> represent the other island.

Angle formed by the helicopter and the two island, θ, is found as follows;

θ = 180° - (15° + 35°) = 130°

By the Law of Sines, we have;

\dfrac{20}{sin(130^{\circ})} = \mathbf{ \dfrac{Distance \ from \  island \ A }{sin(35^{\circ})}}

Which gives;

Distance \ of \ helicopter \ from \  island \ A = \mathbf{ \dfrac{20}{sin(130^{\circ})} \times sin(35^{\circ})}

Mileage \ from \ island \ A =  \dfrac{20}{sin(130^{\circ})} \times sin(35^{\circ}) \times cos(15^{\circ}) \approx 14.5

  • The mileage of the helicopter from the first island is approximately <u>14.5 miles</u>

Learn more about the Law of Sines and Cosines here:

brainly.com/question/8242520

brainly.com/question/2491835

7 0
2 years ago
Can someone pls help me with these!!!!
aliya0001 [1]

Answer:

I hope this helps, sorry for my hand writing

8 0
2 years ago
Find the unit rate for 1/2 mile in 3/10 hour
babunello [35]

Answer:

1 mile for every 0.6 hours

Step-by-step explanation:

0.5 x 2 = 1

3/10 x 2 = 6/10

2 miles = 1.2 hours

4 0
2 years ago
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