All categories

3 years ago

If abc+1=0, prove that: (1/1−a−b^-1)+(1/1−b−c^-1)+(1/1−c−a^−1)=1

Mathematics

1 answer:

shusha [124]3 years ago

6 0

Answer:

Hope it will help. I did it.

Hope the image is clear.

You might be interested in

The perimeter of the flag is 2080 ft what is the flags width and length of the length is 420 ft greater than the width

hram777 [196]

Answer:

The length of the flag is 730 ft and the width is 310 ft

Step-by-step explanation:

The correct question is

The perimeter of the flag is 2080 ft what is the flags width and length if the length is 420 ft greater than the width

Let

L ----> the length of the flag

W ---> the width of the flag

we know that

The perimeter of the flag (rectangle) is equal to

$P=2(L+W)$

we have

$P=2,080\ ft$

$2,080=2(L+W)$

$1,040=L+W$ ----> equation A

$L=W+420$ ---> equation B

Solve the system by substitution

substitute equation B in equation A

$1,040=(W+420)+W$

solve for W

$1,040=2W+420$

$2W=1,040-420$

$2W=620$

$W=310\ ft$

Find the value of L

$L=W+420$ ----> $L=310+420=730\ ft$

therefore

The length of the flag is 730 ft and the width is 310 ft

5 0

3 years ago

The area of a rectangle is 72 cm square. The length of the rectangle is 6 cm longer than the width. What is the width of the rec

miskamm [114]

The correct option will be : B) 6 cm.

Explanation

Suppose, the width of the rectangle is $x$ cm.

As, the length is 6 cm longer than the width, so the length will be: $(x+6) cm.$

Formula for the Area of rectangle is: $(Length)*(Width)$

Given that, the area of a rectangle is 72 cm²

So....

$x(x+6)=72\\ \\ x^2+6x-72=0\\ \\ (x+12)(x-6)=0$

Using zero-product property, we will get...

$x+12=0\\ x= -12$ (Negative value is ignored as width can't be negative)

and

$x-6=0\\ x=6$

So, the width of the rectangle is 6 cm.

6 0

4 years ago

What dose composite mean?

Sveta_85 [38]

Adjective: Made up of various parts or elements

5 0

3 years ago

Two quantities are related, as shown in the table:

mixer [17]

This answer is Y=-1/2x+11 I believe

5 0

4 years ago

Read 2 more answers

Finf the exact value of sin A and cos A where a = 9 and b = 10 and <c is a right angle

Katyanochek1 [597]

To solve for the longest side, the hypotenuse, you have to use the pythagorean theorem. It will be 10^2 + 9^2 = c^2. 100 + 81 =c^2.
c^2 = 181 so c = sqrt(181).
to find sin of A do opposite/hypotenuse which gives you 9/sqrt(181)
to find cos of A do adjacent/hypotenuse which gives you 10/sqrt(181)

8 0

3 years ago

Read 2 more answers

If abc+1=0, prove that: (1/1−a−b^-1)+(1/1−b−c^-1)+(1/1−c−a^−1​)=1​

If abc+1=0, prove that: (1/1−a−b^-1)+(1/1−b−c^-1)+(1/1−c−a^−1)=1