Answer:
yes
Step-by-step explanation:
The line intersects each parabola in one point, so is tangent to both.
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For the first parabola, the point of intersection is ...
y^2 = 4(-y-1)
y^2 +4y +4 = 0
(y+2)^2 = 0
y = -2 . . . . . . . . one solution only
x = -(-2)-1 = 1
The point of intersection is (1, -2).
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For the second parabola, the equation is the same, but with x and y interchanged:
x^2 = 4(-x-1)
(x +2)^2 = 0
x = -2, y = 1 . . . . . one point of intersection only
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If the line is not parallel to the axis of symmetry, it is tangent if there is only one point of intersection. Here the line x+y+1=0 is tangent to both y^2=4x and x^2=4y.
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Another way to consider this is to look at the two parabolas as mirror images of each other across the line y=x. The given line is perpendicular to that line of reflection, so if it is tangent to one parabola, it is tangent to both.
Here you have: 2x^2-9x-26
Answer: 108deg
From picture:
10z=pi and m<SPT =6z So we know 20z=2pi or 360deg
Let’s solve:
20z=2pi
z=pi/10
m<SPT=6z=6pi/10=3pi/5 now lets take the angle from radians to degrees by unit conversion:
3pi/5*(180deg/pi)=108deg
Answer:
Volume is 718 cm^3
Step-by-step explanation:
We need to get the radius of cylinder A
From the base area,
we have that;
A = pi * r^2
18 = 3.142 * r^2
r^2 = 18/3.142
r^2 = 5.73
r= √5.73
r = 2.39
If two shapes are similar, we have the ratio of their corresponding sides equal;
Thus;
2.39/5 = x/10
x = (10 * 2.39)/5
x = 4.78 cm
To get the volume, we use the formula
V = pi * r^2 * h
V = 3.142 * 4.78^2 * 10
V = 717.8 cm^3
This is approximately 718 cm^3
Answer:
The critical value can be founded in the normal standard distribution table using the value of 
and we got 
. Replacing the info given we got:
Step-by-step explanation:
For this case we have the following info given:
represent the population deviation
represent the sample mean
represent the sample size
And we want to find the margin of error for a confidence level of 95%. So then the significance level would be 
and . The margin of error is given by:
The critical value can be founded in the normal standard distribution table using the value of and we got . Replacing the info given we got:
