Let x and y be the two integers.
The sum of the integers is x+y while the difference is x-y assuming x is larger than y.
If x+y > x-y, then
x+y > x-y
x+y-x > x-y-x
y > -y
y+y > -y+y
2y > 0
2y/2 > 0/2
y > 0
So as long as y is positive, this makes the sum greater than the difference
For example, if x = 10 and y = 2, then
x+y = 10+2 = 12
x-y = 10-2 = 8
clearly 12 > 8 is true
If y is some negative number (say y = -4), then
x+y = 10+(-4) = 10-4 = 6
x-y = 10-(-4) = 10+4 = 16
and things flip around
Saying a blanket statement "the sum of two integers is always greater than their difference" is false overall. If you require y to be positive, then it works but as that last example shows, it doesn't always work.
So to summarize things up, I'd say the answer is "no, the statement isn't true overall"
Answer:
Step-by-step explanation:
The image contains the work.
<h2>
Answer:</h2>
The different possible routes are :
181440
<h2>
Step-by-step explanation:</h2>
We are asked to find the number of different routes that are possible to choose 7 locations among the 9 locations remaining.
This means that we have to chose the locations and also we have to arrange them in different orders according to the different order of locations.
The method we have to use is a method of permutation.
When we have to chose and arrange r items out of a total of n items then the formula is given by:
Here we have: n=9
and r=7
Hence, the different possible routes are:
Hence, the answer is:
181440
Answer:
1500
Step-by-step explanation:
Since k is constant (the same for every point), we can find k when given any point by dividing the y-coordinate by the x-coordinate.
