Answer:
95% confidence interval for the variance of the bowling ball weight is between a lower limit of 13.328 pounds and an upper limit of 14.672 pounds.
Step-by-step explanation:
Confidence interval is given as weight +/- margin of error (E)
weight = 14 pounds
sample sd = 0.94 pound
n = 10
degree of freedom = n - 1 = 10 - 1 = 9
confidence level (C) = 95% = 0.95
significance level = 1 - C = 1 - 0.95 = 0.05 = 5%
critical value (t) corresponding to 9 degrees of freedom and 5% significance level is 2.262
E = t × sample sd/√n = 2.262×0.94/√10 = 0.672 pounds
Lower limit of weight = weight - E = 14 - 0.672 = 13.328 pounds
Upper limit of weight = weight + E = 14 + 0.672 = 14.672 pounds.
95% confidence interval is (13.328, 14.672)
SA = 4 * (pi) * r^2......solving for (pi)
divide both sides by 4r^2
SA / (4r^2) = (pi)
Answer:
A and F
Step-by-step explanation:
A and F both represent instances of division of 14/5
B represent multiplication
C represent the reciprocal of the problem, 5/14
D represent addition
Answer:
c = 7.5 meters.
Step-by-step explanation:
hello :
use phtagore - rule :
c² = 6²+4.5²
c² = 36 + 20.25
c² =56.25
c = √56.25
c = 7.5 meters.
Answer:
This is the answer of your question 6.3125
