Answer:
0%
Explanation:
This involves a single gene coding for melanin pigment in the skin. The recessive form of this gene (allele) is albinism while the dominant form is a normal skin. The question highlights that the normal male parent (dominant) has no family history of albinism, this means that nobody in their family has ever possessed albinism or has been a carrier/heterozygous for the trait. This is because a carrier/heterozygote will always produce the recessive trait (albinism) if crossed with another carrier or albino individual.
In a nutshell, the normal male parent is homozygous for the dominant trait. Hence, if a homozygous dominant male is crossed with an albino woman (homozygous recessive), all their offsprings will possess a heterozygous genotype and dominant phenotype. Meaning that none of their children will ba an albino.
Hence, the percentage of their child being an albino is 0.
Answer: Flow of electric charges- current
Opposition to the flow of electric current- resistance
Stored potential energy at the source of a circuit- Voltage
Explanation:
The probable genotype of the IV-3 with the perspective of autosomal inheritance will be A because he does not have condition A. Therefore both parents must be in condition A.
The probable genotype of IV-3 with the perspective of set=linked inheritance will be BbY this is because he has B condition. Therefore the mothers' genotype must be XBXb and the father's genotype must be XBY.
The probability of IV-4 having condition A is 1/36
Answer:
The answer is D a retrovirus inserts DNA into the host cells genes
