This involves a single gene coding for melanin pigment in the skin. The recessive form of this gene (allele) is albinism while the dominant form is a normal skin. The question highlights that the normal male parent (dominant) has no family history of albinism, this means that nobody in their family has ever possessed albinism or has been a carrier/heterozygous for the trait. This is because a carrier/heterozygote will always produce the recessive trait (albinism) if crossed with another carrier or albino individual.
In a nutshell, the normal male parent is homozygous for the dominant trait. Hence, if a homozygous dominant male is crossed with an albino woman (homozygous recessive), all their offsprings will possess a heterozygous genotype and dominant phenotype. Meaning that none of their children will ba an albino.
Hence, the percentage of their child being an albino is 0.
Biologists studying disease susceptibility in mice used genetic techniques to look for gene flow in 12 wild populations of mice. The populations (designated A through L) were located along a 210-km transect line.
