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3 years ago

Can someone help me please

Mathematics

1 answer:

marysya [2.9K]3 years ago

8 0

Answer:

Step-by-step explanation:

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An engineering crew ran several tests on a new automobile engine they were designing. The mean fuel consumption was 52.4 miles p

zhenek [66]

Any value which is more than 2 standard deviations away from the mean is considered to be "unusual."

2 standard deviations above the mean 52.4 mp would be 52.4+2(1.8), or 56; 2 std devs below the mean would be 52.4 - 2(1.8), or 48.8. Thus, any value larger than 56 or any value smaller than 48.8 would be "unusual."

54.8, 49.1 and 51.3 are not unusual; 56.5 is unusual, because it's greaster than 56.

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3 years ago

1/4-5/8n is equivalent to p(2-5n)

hodyreva [135]

Answer:

1/4 - 5/8n = p ( 2- 5n

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2 years ago

The graphs below have the same shape what is the equation of the red graph

Lisa [10]

Well , I think it’s c

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3 years ago

A multiple-choice examination has 20 questions, each with five possible answers, only one of which is correct. Suppose that one

kari74 [83]

Answer:

The probability that the student answers at least seventeen questions correctly is $8.03\times 10^{-10}$ .

Step-by-step explanation:

Let the random variable X represent the number of correctly answered questions.

It is provided all the questions have five options with only one correct option.

Then the probability of selecting the correct option is,

$P(X)=p=\frac{1}{5}=0.20$

There are n = 20 question in the exam.

It is also provided that a student taking the examination answers each of the questions with an independent random guess.

Then the random variable can be modeled by the Binomial distribution with parameters n = 20 and p = 0.20.

The probability mass function of X is:

$P(X=x)={20\choose x}\ 0.20^{x}\ (1-0.20)^{20-x};\ x =0,1,2,3...$

Compute the probability that the student answers at least seventeen questions correctly as follows:

$P(X\geq 17)=P (X=17)+P (X=18)+P (X=19)+P (X=20)$

$=\sum\limits^{20}_{x=17}{{20\choose x}\ 0.20^{x}\ (1-0.20)^{20-x}}\\\\=0.00000000077+0.000000000032+0.00000000000084+0.000000000000042\\\\=0.000000000802882\\\\=8.03\times10^{-10}$

Thus, the probability that the student answers at least seventeen questions correctly is $8.03\times 10^{-10}$ .

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3 years ago

What are the factors of x2-144

padilas [110]

Answer:

(x+12)(x-12)

Step-by-step explanation:

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2 years ago

Read 2 more answers