0.3*42 this gives you a 30% discount
3/10*42 this gives you a 30% discount
0.03*42 this gives you a 3% discount
3 *4.2 This is not a discount
Answer:
1240.4 mm²
Step-by-step explanation:
SA of Pentagonal pyramid:
(as)(5/2) + (sl)(5/2)
↑ ↑
base area lateral area
_____________________
a: apothem (in-radius) length, s: side length.
l: slant height.
______________________
Since we are already given the base area which is 440.4 mm². All we need to do is find the lateral area and add both areas together.
Given that the triangular face of the lateral part has a side/base length of 16mm, and a 20mm slant height.
A triangle has an area of ½bh and since there are 5 of these faces total, (5)(½bh) = (5/2)(bh). In a three dimensional perspective, b will be s and h will be l so (sl)(5/2).
With this information the surface area is:
(16)(20)(5/2)mm + (440.4 mm²) →
800 mm² + 440.4 mm² =
1240.4 mm²
Answer:
The value is 
Step-by-step explanation:
From the question we are told that
The weight of the bucket is 
The depth of the well is 
The weight of the water is 
The rate at which the bucket with water is pulled is 
The rate of the leak is 
Generally the workdone is mathematically represented as
]
Here G(x) is a function defining the weight of the system (water and bucket ) and it is mathematically represented as

Here I is the rate of water loss in lb/ft mathematically represented as

=> 
=>
So

=> 
So
]
=> ![W = [47x - \frac{0.1x^2}{2} ]|\left 60} \atop {0}} \right.](https://tex.z-dn.net/?f=W%20%3D%20%20%5B47x%20-%20%5Cfrac%7B0.1x%5E2%7D%7B2%7D%20%5D%7C%5Cleft%2060%7D%20%5Catop%20%7B0%7D%7D%20%5Cright.)
=> ![W= [47(60) - 0.05(60)^2]](https://tex.z-dn.net/?f=W%3D%20%5B47%2860%29%20-%200.05%2860%29%5E2%5D)
=> 
So...
-2(16-4x)-8=6(x+2) Multiply
-32+8x-8=6x+12 Add like terms
-40+8x=6x+12 Subtract 6x from both sides
-40+2x=12 Add 40 to both sides
2x=52 Divide 2 from both sides
x=26 Substitute to check
-2(16-4(26))-8=6((26)+2) Add and multiply in parenthesis
-2(-88)-8=6(28) Multiply
176-8=168 Subtract
168=168
So x=26
I hope this helps! Have a great day!