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Anna11 [10]
3 years ago
15

Work out the area of a rectangle with base, b = 20mm and perimeter, P = 42mm.

Mathematics
2 answers:
polet [3.4K]3 years ago
6 0

Answer:

Let the length of the rectangle be 'l'

We have,

Perimeter of rectangle, P = 42mm.

or, 2(l+b) = 42\\or, l +b = \frac{42}{2} = 21\\or, l + 20 = 21\\or, l = 1mm\\

Area of rectangle = lb = 1(20) = 20mm^{2}

Zarrin [17]3 years ago
3 0

Answer:

20mm

Step-by-step explanation:

base=20mm

base x 2 because there are two long lines

20 x 2 = 40

42-40=2

amount needed on either side to balance

height=1mm

20 x 1 = 20mm

area = 20mm

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Answer:

The quotient is (10x - 5) and the reminder is -50 ⇒ 1st answer

Step-by-step explanation:

* Lets solve the long division by easiest way

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∵ (10x² - 85x - 10) is the dividend

∵ (x - 8) is the divisor

- Divide the first term of the dividend by the first term of the divisor

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# -10

∴ (10x² - 85x - 10)/(x - 8) = 10x + (-5x - 10)/(x - 8)

* Repeat the same steps again with the new dividend -5x - 10

- Divide the first term of the dividend by the first term of the divisor

∴ -5x ÷ x = -5 ⇒ second term of the quotient

- Multiply -5 by the divisor

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- Subtract the answer from the dividend

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# -5x - -5x = -5x + 5x = 0

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∴ (10x² - 85x - 10)/(x - 8) = 10x - 5 + -50/(x - 8)

- The quotient is the answer of the division

∴ The quotient is (10x - 5) and the reminder is -50

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