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Lyrx [107]
3 years ago
11

A washer and a dryer cost $928 combined. The washer costs $78 more than the dryer. What is the cost of the dryer?

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
4 0

Answer:

Step-by-step explanation:

$425

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Question 40 is D because from looking at the graph, its is symmetrical and the mean is the average, which usually the middle of the graph, so is the median. The median and mean would be within the 2.1-3 category because its the middle of the graph.

Question 41 is B because every pound is 16 ounces. If you multiply 16 and 12.5, you'll get 200.
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A + (b + c) = (A + b) + c<br><br><br> What property is this equation
Free_Kalibri [48]

Answer:

Step-by-step explanation:

Associative property

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3 years ago
Active ingredient of a pill comprises 45% of the pill mass. If a pill contains 325 mg of active ingredient,
uranmaximum [27]

Answer:

Step-by-step explanation:

The idea here is to be able to write and then solve the equation needed for this. In words, this is what you are looking to solve: "The active ingredinet is 45% of the mass of the pill". Putting those words into an equation:

active ingredient = .45 (mass of pill). Since our active ingredient is 35 mg:

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6 0
3 years ago
I need help with this problem please
GrogVix [38]

Answer:

j = 2/3

Step-by-step explanation:

-1/3 = -1/2 j

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3 0
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Read 2 more answers
Average Temperatures Suppose the temperature (degrees F) in a river at a point x meters downstream from a factory that is discha
mr Goodwill [35]

Answer:

Step-by-step explanation:

Average Temperatures Suppose the temperature (degrees F) in a river at a point x meters downstream from a factory that is discharging hot water into the river is given by

T(x) = 160-0.05x^2

a. [0, 10]

For x = 0

T(0) = 160 - 0.05 × 0^2

T(0) = 160

For x = 10

T(10) = 160 - 0.05 × 10^2

T(10) = 160 - 5 = 155

The average temperature

= (160 + 155)/2 = 157.5

b. [10, 40]

For x = 10

T(10) = 160 - 0.05 × 10^2

T(10) = 160 - 5 = 155

For x = 40

T(10) = 160 - 0.05 × 40^2

T(10) = 160 - 80 = 80

The average temperature

= (80 + 155)/2 = 117.5

c. [0, 40]

For x = 0

T(0) = 160 - 0.05 × 0^2

T(0) = 160

For x = 40

T(10) = 160 - 0.05 × 40^2

T(10) = 160 - 80 = 80

The average temperature

= (160 + 80)/2 = 120

6 0
3 years ago
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