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KATRIN_1 [288]
2 years ago
11

So how do u add fractions?​

Mathematics
2 answers:
Diano4ka-milaya [45]2 years ago
8 0

Answer:

magic

Step-by-step explanation:

Make sure the bottom number are the same

Add the top numbers,put that answer over the denominator

Simplify the fractions if needed

Alecsey [184]2 years ago
3 0

Answer:

Cross-multiply the two fractions and add the results together to get the numerator of the answer.

Suppose you want to add the fractions 1/3 and 2/5. To get the numerator of the answer, cross-multiply. In other words, multiply the numerator of each fraction by the denominator of the other:

1/3 and 2/5

5+1=6     3+2=5

Add the results to get the numerator (top) of the answer:

5 + 6 = 11

Multiply the two denominators together to get the denominator of the answer.

To get the denominator (bottom), just multiply the denominators of the two fractions:

1/3 and 2/5

3x5 = 15

The denominator of the answer is 15.

So the final answer is 11/15

HOPE THIS HELPS!

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if Dion drove to Phoenix at a rate of 60 miles per hour and the return trip he drove 50 miles per hour and it took him one am ho
kykrilka [37]

60mph=?hrs

50mph=?+1hr

?=6hrs


3 0
3 years ago
I'm very confused <br> Please help ASAP!!!
harina [27]

Answer:

First case

0.3m = r

0.3m = 18

m = 18/0.3

m = 60 mins.

Second case

0.3m = r

0.3 x 180 = r

r = 54 rows

Third case

0.3m = r

0.3m = 72

m = 240 minutes

Fourth case

0.3m = r

0.3 x 360 = r

r = 108 rows

Hope this helps!

4 0
3 years ago
Read 2 more answers
Don't understand need help
Nostrana [21]
Hello!
So, your questions are basically having to do with rotations. This means to rotate certain points in a grid.
The following are formulas for solving rotations-
90 Degrees Clockwise About The Origin = (X,Y) -> (Y,-X)
180 Degrees About The Origin = (X,Y) -> (-X,-Y)
270 Degrees Clockwise About The Origin = (X,Y) -> (-Y,X)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~
90 Degrees Counterclockwise = 270 Clockwise
270 Degrees Counterclockwise = 90 Clockwise
~~~~~~~~~~~~~~~~~~~~~~~~~~~~
*Note, in the formulas, the negative sign only stands for the opposite. So if your original point is a negative, it will become positive,
~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Now that we have our formulas, let's put them into affect with your points.

13)  90 Degrees CC = 270 Degrees Clockwise. Formula- (X,Y) -> (-Y,X)
A (2,-2) -> A' (2,2)
B (4,-1) -> B' (1,4)
C (4,-3) -> C' (3,4)
D (2,-4) -> D' (4,2)

*Note, the symbol _'_ Stands for prime. All this means, is the new point.

15) Now, I apologize, but I'm a bit confused on this one :( When it says about point L, I can't tell if it just wants that one point, or the whole figure translated. Again, I am so sorry :(

17) This one I do know. 270 degrees CC = 90 degrees Clockwise. Formula- (X,Y) = (Y,-X).
W (-6,-2) -> W' (-2,6)
X (-2,-2) -> X' (-2,2)
Y (-2,-6) -> Y' (-6,2)
Z (-5,-6) -> Z' (-6,5)

Hope this helped! Again, sorry about number 15. Have a great day!
Regards,
~KayEmQue


7 0
3 years ago
find all local maximum and minimum points by the second derivative test when possible y=2+3×+3 (b) y=6×+sin3×​
inessss [21]

Answer:

Step-by-step explanation:

Given a function f, whose derivatives are f' and f'', a value x is a critical point if f'(x) =0. A value x is a minimum of f if it is a critical point and f''(x) >0 and it is maximum if f''(x)<0. We will perfom the following steps:

1. Calculate the derivative f'.

2. Solve f'(x) =0.

3. Determine if the x value found in 2 is a minimum or a maximum using f''.

Recall the following properties of derivatives

(\sin(x)) ' = \cos(x)

(\cos(x))' = -\sin(x)

(cf(x))' = cf'(x) where c is a constant.

(x^n)' = nx^{n-1}

(f+g)' = f'+g' where f,g are differentiable.

(c)' =0 where c is a constant.

(f(g(x))' = f'(g(x)) \cdot g'(x) (chain rule)

Case 1: f(x) = 2+3x+3.

Using the properties from above, we have

1. f'(x) = 0+3+0 = 3

2. The equation f'(x)=0 where f'(x) = 3 has no solution.

3. Based on the previous result, f has no maximum nor minimum.

Case 2: f(x) = 6x+\sin(3x)

1. f'(x) = 6+3\cos(3x)

2. We have the equation

6+3\cos(3x)=0

which is equivalent to

\cos(3x) = -2

Recall that the cosine function only takes values in the set [-1,1]. So, this equation has no solution.

3. Based on the previous result, f has no maximum nor minimum.

8 0
3 years ago
P(z) =3z - 7 when z= 3+h<br><br>Evaluate the function.<br><br>I give Brainliest!
True [87]

Answer:

=3h+2

Step-by-step explanation:

p(z) =3z - 7 whenz= 3+h

p(z) =3(3+h) - 7

      =9+3h-7

      =3h+2

3 0
3 years ago
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