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1 year ago

What are the measures of angle b e c and angle a b e in the figure shown? (30 points.)

Mathematics

2 answers:

koban [17]1 year ago

8 0

Angle bec= 20 and angle abe =160

IgorC [24]1 year ago

4 0

Answer:

4x+10-32x3

Step-by-step explanation:

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32=32+? I need help its annoyings

Andreyy89

Answer:

Step-by-step explanation:

32=32+0

5 0

3 years ago

Read 2 more answers

Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.

Maurinko [17]

Answer:

616 square centimeters

Step-by-step explanation:

Area of a circle is equal to pi × r^2. In this case, they have asked that you substitute 3.14 or 22/7 for pi, so I will be using 22/7, instead.

Diameter is equal to 2r; to find the radius, simply divide 28 by two. This gives us a radius of 14.

Multiply 14 squared by 22/7:

(22/7)(14^2)

This gives us (22/7)(196); (4312/7); 616.

Therefore, the area of the circle is approximately 616 square centimeters.

8 0

2 years ago

!!!!Which ordered pair in the form of (x, y) are solutions to the equation 7x - 5y =28

muminat

Answer:

(-6,-14)

Step-by-step explanation:

8 0

3 years ago

There are 2112 people in a concert.

nadya68 [22]

Answer:

75% of 352 children are boys

Step-by-step explanation:

If 5/6 of the people participaticipants to a concert are adults then 1 out of 6 prople are children so we may reach a number of 2112:6=352 children

if 25% of the children are girls then 75% are boys

88×3=264 boys

7 0

3 years ago

Solve the system of equations using matrices. Use the Gauss- Jordan elimination method And find a solution set

KATRIN_1 [288]

$\begin{gathered} x+y+z=4 \\ x-y-z=0 \\ x-y+z=8 \\ \text{The system using matrix is} \\ \begin{bmatrix}{1} & {1} & {1}, & {4} \\ {1} & {-1} & {-1,} & {0} \\ {1} & {-1} & {1,} & {8}{}{}\end{bmatrix}\rightarrow F2=F2-F1=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {-2} & {-2,} & {-4} \\ {1} & {-1} & {1,} & {8}{}{}\end{bmatrix} \\ \rightarrow F3=F3-F1=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {-2} & {-2,} & {-4} \\ {0} & {-2} & {0,} & {4}{}{}\end{bmatrix}\rightarrow F2=-\frac{1}{2}F2 \\ =\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {-2} & {0,} & {4}{}{}\end{bmatrix}\rightarrow F3=F3+2F2=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {0} & {2,} & {8}{}{}\end{bmatrix}\rightarrow F3=\frac{1}{2}F3 \\ =\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix}\rightarrow F2=F2-F3=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix} \\ \rightarrow F1=F1-F3=\begin{bmatrix}{1} & {1} & {0}, & {0} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix}\rightarrow F1=F1-F2 \\ =\begin{bmatrix}{1} & {0} & {0}, & {2} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix} \\ \text{Therefore, the solution is }x=2,\text{ y=-2 and z=4} \end{gathered}$

6 0

1 year ago