Answer:
a=3 and b=-2
Step-by-step explanation:
We are given that five terms of a quadratic sequence are
1 8, 21, 40, 65.
The nth term of this sequence
=
We have to find the value of a and b where a and b are integers.
For n=1
......(1)
For n=2

.....(2)
Subtract equation (1) from (2) we get


Using the value of a=3 in equation (1)


Hence, the value of
a=3 and b=-2
"<span>5 to the negative 4th power over 5 to the 3rd</span>" translates to
5⁻⁴ / 5³
So you can just combine exponents.
5⁻⁴ / 5³ = 5⁻⁴ ⁻ ³ = 5⁻⁷ = 1/5⁷
Final answer: 1/5⁷
3 4/5 because when you make the denominators equal by multiplying 1/4 by 5 on both sides and 4/5 by 4 and both sides you will get 5/20 and 16/20
I think it would be y=(-9/5)x -1/9