The first five terms of the recursively defined sequence are 6, 12, 48, 768, 196608
For given question,
We have been given the recursive formula of a sequence.

Also, the first term of the sequence is,
a1 = 6
Substitute k = 1 in given recursive formula.
⇒ 
⇒ a2 = 1/3 (6)²
⇒ a2 = (1/3) × 36
⇒ a2 = 12
Substitute k = 2 in given recursive formula.
⇒ 
⇒ a3 = (1/3) × (12)²
⇒ a3 = (1/3) × 144
⇒ a3 = 48
Substitute k = 3 in given recursive formula.
⇒ 
⇒ a4 = (1/3) × (48)²
⇒ a4 = (1/3) × 2304
⇒ a4 = 768
Substitute k = 4 in given recursive formula.
⇒ 
⇒ a5 = (1/3) × (768)²
⇒ a5 = (1/3) × 589824
⇒ a5 = 196608
Therefore, the first five terms of the recursively defined sequence are 6, 12, 48, 768, 196608
Learn more about the recursive formula of sequence here:
brainly.com/question/14457800
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Hey there!
All you need to do is multiply the beats per minute by 15 minutes.
72 x 15=1080. Your heart will beat 1080 times in 15 minutes.
I hope this helps!
Emmmm derecha izquierda 56 a la cuadrada de 4 triangulada sobre17 raíz 12
Answer:
D) g(x) is shifted 4 units to the left and 6 units down
Step-by-step explanation:
When -6 is added to the y-value, it moves the point on the graph down 6 units. Compared to f(x), g(x) is 6 units down.
Transforming the function using f(x -h) shifts its graph h units to the right. Here, we have h=-4, so the graph is shifted 4 units to the left.
Not really sure but 4 and the other - and the 0 so yes.