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The solutions of the equation are -12 and 16
Step-by-step explanation:
Absolute value describes the distance of a number on the number line from 0 without considering which direction from zero the number lies. The absolute value of a number is never negative, if IxI = a, where a > 0, then
∵ 2Ix - 2I - 8 = 20
- At first add 8 to both sides
∴ 2Ix - 2I = 28
- Then divide both sides by 2
∴ Ix - 2I = 14
Now By using the notes above equate x - 2 by 14 and -14
∵ x - 2 = 14
- Add 2 to both sides
∴ x = 16
∵ x - 2 = -14
- Add 2 to both sides
∴ x = -12
The solutions of the equation are -12 and 16
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Answer:
0<x<1
Step-by-step explanation:
(x+3)(x−4)<−12
FOIL
x^2 -4x+3x -12 <-12
x^2 -x -12 <-12
Add 12 to each side
x^2 -x -12+12 <-12+12
x^2 -x <0
Factor out an x
x(x-1) <0
Using the zero product property
x(x-1) =0
x=0 x-1=0
x=0 x=1
Check the ranges
x<0
x(x-1) <0
- * - >0
False
0<x<1
x(x-1) <0
+ * - <0
True
x>1
x(x-1) <0
+ * + >0
False
C, the median is 23 when you add 13 + 10. Then you divide 23 and 2.
