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vovangra [49]
2 years ago
14

3 The formula to find the area of a rectangle is A = lw. If l = 6 in and w = 5 in, then what is the area of the blue portion of

the rectangle? A. 11 sq in B. 22 sq in C. 15 sq in D. 30 sq in

Mathematics
1 answer:
Serga [27]2 years ago
7 0

Answer:C. 15

Step-by-step explanation:

Its 15 because the rectangle is 30 and the blue side is half of it so you would have to divide 30 by 2

30 ÷ 2 = 15

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In the expression what is the numerical coefficient in this question ?
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-7

Step-by-step explanation:

The numerical coefficient of - 7yz^2 is - 7.

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Consider Functions F and G
Zanzabum

Answer:

A

Step-by-step explanation:

We are given two functions:

\displaystyle f(x)=\frac{x-16}{x^2+6x-40}\text{ and } g(x)=\frac{1}{x+10}

And we want to find:

f(x)+g(x)

Thus:

\displaystyle =\frac{x-16}{x^2+6x-40}+\frac{1}{x+10}

We can factor the denominator of the first term:

\displaystyle =\frac{x-16}{(x+10)(x-4)}+\frac{1}{x+10}

In order to add the two terms, we must have a common denominator. To achieve this, we can multiply to second term by (x - 4). Therefore:

\displaystyle =\frac{x-16}{(x+10)(x-4)}+\frac{1}{x+10}\Big(\frac{x-4}{x-4}\Big)

Multiply:

\displaystyle =\frac{x-16}{(x+10)(x-4)}+\frac{x-4}{(x+10)(x-4)}

Combine:

\displaystyle =\frac{(x-16)+(x-4)}{(x+10)(x-4)}

Simplify:

\displaystyle =\frac{2x-20}{(x+10)(x-4)}

We can expand the denominator:

\displaystyle =\frac{2x-20}{x^2+6x-40}

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MA_775_DIABLO [31]

The expression without using absolute value is 2z - 11

<h3>Absolute value of a function</h3>

Given the expression with absolute value expressed as:

lz-6l-lz-5l

Since absolute function can both be negative or positive, hence;

lz-6l-lz-5l = z - 6 - -(z - 5)

lz-6l-lz-5l = z-6-(-z+5)

lz-6l-lz-5l = z - 6 + z - 5

lz-6l-lz-5l = 2z - 11

Hence the expression without using absolute value is 2z - 11

Learn more on absolute value here: brainly.com/question/729268

#SPJ1

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