A. (-3,0) thats the answer i have
Vertex at the origin and opening down → y=ax^2
Width: w=16
x=w/2→x=16/2→x=8
x=8, y=-16→y=ax^2→-16=a(8)^2→-16=a(64)→-16/64=a(64)/64→-1/4=a→a=-1/4
y=ax^2→y=-(1/4)x^2
7 m from the edge of the tunnel → x=w/2-7=8 m-7 m→x=1 m
x=1→y=-(1/4)x^2=-(1/4)(1)^2=-(1/4)(1)→y=-1/4
Vertical clearance: 16-1/4=16-0.25→Vertical clearance=15.75 m
Please, see the attached file.
Answer: Third option 15.75 m
Answer:
could you maybe give me a better picture in the light or something? it is hard for me to see it
Step-by-step explanation:
Answer:
x = 10
Step-by-step explanation:
Answer:
The surface area of Triangular base Prism = 3682 cm²
Step-by-step explanation:
Given in question as :
For a Triangular base prism ,
The base of prism (b) = 24 cm
The height of prism (l) = 29 cm
Each side length (s) = 37 cm
The height of base triangle ( h ) = 35 cm
Hence , we know that The surface area of Triangular base prism is
= (b×h) + (2×l×s) + (l×b)
= (24×35) + (2×29×37) + (29×24)
= (840) + (2146) + (696)
= 3682 cm²
Hence The surface area of Triangular base Prism is 3682 cm² Answer