Question

Divide (-3x^2 - 9x) ÷ (x + 3) please explain/show work! <33

Answer 1

Step-by-step explanation:

$( - 3 {x}^{2} - 9x) \div (x + 3)$

This is the original equation so you will open the brackets.

$- 3 {x}^{2} - 9x \div x + 3$

The x will cross the division sign making it times x.

$3 {x}^{2} - 9x \times x = 3$

So you will proceed to multiply the 9x by x making it;

$3 {x}^{2} - 9 {x}^{2} = 3$

So you will subtract 9x² from 3x² which won't be possible so it will be negative.

$- 6 {x}^{2} = 3$

Then you will square root both sides making it;

$- \sqrt{6 {x}^{2} } = \sqrt{3}$

So the ² will cancel the √ leaving

-6x=√3

-6x=1.73(Divide both sides by -6)

x=0.288

That's the final answer.