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prisoha [69]
3 years ago
12

What is the interest on 350.00 invested 4 years at a 5% simple interest?

Mathematics
1 answer:
mote1985 [20]3 years ago
7 0
$70 in 4 years at a 5%
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Gary wants to buy a video game with a selling price of $48, on sale for 50% off. The sales tax in his state is 4.5%. How much wi
Anna [14]

Answer:

$25.20

Step-by-step explanation:

First, take the 50% off the sales price:

($48)*(-0.50) = -$24.

($48 - $24) = $24 sale price.

Tax on $24 is ($24)*(0.05) = $1.20

Add the price and sales tax:

$24 + $1.20 = $25.20

5 0
3 years ago
Write Y=4/3x-4 in slope intercept form
sergij07 [2.7K]

Answer:

Y=4/3x-4

Step-by-step explanation:

You have it in slope intercept form =)

7 0
3 years ago
Using the numbers 4.3, -1.07, and -2.917, write an expression containing both addition and subtraction that simplifies to a nega
Advocard [28]

Answer:

-1.07+(-2.917)-4.3=-8.287

Step-by-step explanation:

6 0
3 years ago
chris runs 2.3 miles every day of the week, except sunday. on sunday he only runs 2 miles. how many miles will he run in 2 weeks
Ludmilka [50]

Answer:

He will run 31.6 miles in two weeks.

Step-by-step explanation:

6 days a week = 2.3 miles

6 days · 2 weeks = 12 days total running 2.3 miles

1 day a week = 2 miles

1 day · 2 weeks = 2 days total running 2 miles

(12 · 2.3) + (2 · 2)

27.6 + 4

31.6 miles

7 0
3 years ago
Evaluate using <br> Definite integrals
swat32

Since [0,4]=[0,1]\cup(1,4], we can rewrite the integral as

\displaystyle \int_0^1f(t)\;dt + \int_1^4 f(t)\; dt

Now there is no ambiguity about the definition of f(t), because in each integral we are integrating a single part of its piecewise definition:

\displaystyle \int_0^1f(t)\;dt = \int_0^11-3t^2\;dt,\quad \int_1^4 f(t)\; dt = \int_1^4 2t\; dt

Both integrals are quite immediate: you only need to use the power rule

\displaystyle \int x^n\;dx=\dfrac{x^{n+1}}{n+1}

to get

\displaystyle \int_0^11-3t^2\;dt = \left[t-t^3\right]_0^1,\quad \int_1^4 2t\; dt = \left[t^2\right]_1^4

Now we only need to evaluate the antiderivatives:

\left[t-t^3\right]_0^1 = 1-1^3=0,\quad \left[t^2\right]_1^4 = 4^2-1^2=15

So, the final answer is 15.

4 0
3 years ago
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