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prisoha [69]
3 years ago
12

What is the interest on 350.00 invested 4 years at a 5% simple interest?

Mathematics
1 answer:
mote1985 [20]3 years ago
7 0
$70 in 4 years at a 5%
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50(b+5) - 68 + 23 HELLPPP
lbvjy [14]

Answer:

50b+205

Step-by-step explanation:

Yes sir

6 0
3 years ago
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A 75-gallon tank is filled with brine (water nearly saturated with salt; used as a preservative) holding 11 pounds of salt in so
Debora [2.8K]

Let A(t) = amount of salt (in pounds) in the tank at time t (in minutes). Then A(0) = 11.

Salt flows in at a rate

\left(0.6\dfrac{\rm lb}{\rm gal}\right) \left(3\dfrac{\rm gal}{\rm min}\right) = \dfrac95 \dfrac{\rm lb}{\rm min}

and flows out at a rate

\left(\dfrac{A(t)\,\rm lb}{75\,\rm gal + \left(3\frac{\rm gal}{\rm min} - 3.25\frac{\rm gal}{\rm min}\right)t}\right) \left(3.25\dfrac{\rm gal}{\rm min}\right) = \dfrac{13A(t)}{300-t} \dfrac{\rm lb}{\rm min}

where 4 quarts = 1 gallon so 13 quarts = 3.25 gallon.

Then the net rate of salt flow is given by the differential equation

\dfrac{dA}{dt} = \dfrac95 - \dfrac{13A}{300-t}

which I'll solve with the integrating factor method.

\dfrac{dA}{dt} + \dfrac{13}{300-t} A = \dfrac95

-\dfrac1{(300-t)^{13}} \dfrac{dA}{dt} - \dfrac{13}{(300-t)^{14}} A = -\dfrac9{5(300-t)^{13}}

\dfrac d{dt} \left(-\dfrac1{(300-t)^{13}} A\right) = -\dfrac9{5(300-t)^{13}}

Integrate both sides. By the fundamental theorem of calculus,

\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac1{(300-t)^{13}} A\bigg|_{t=0} - \frac95 \int_0^t \frac{du}{(300-u)^{13}}

\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac{11}{300^{13}} - \frac95 \times \dfrac1{12} \left(\frac1{(300-t)^{12}} - \frac1{300^{12}}\right)

\displaystyle -\dfrac1{(300-t)^{13}} A = \dfrac{34}{300^{13}} - \frac3{20}\frac1{(300-t)^{12}}

\displaystyle A = \frac3{20} (300-t) - \dfrac{34}{300^{13}}(300-t)^{13}

\displaystyle A = 45 \left(1 - \frac t{300}\right) - 34 \left(1 - \frac t{300}\right)^{13}

After 1 hour = 60 minutes, the tank will contain

A(60) = 45 \left(1 - \dfrac {60}{300}\right) - 34 \left(1 - \dfrac {60}{300}\right)^{13} = 45\left(\dfrac45\right) - 34 \left(\dfrac45\right)^{13} \approx 34.131

pounds of salt.

7 0
1 year ago
Find the missing probability.<br><br> P(A)=13/20,P(A∩B)=13/25,P(B|A)=?
Tju [1.3M]

By definition of conditional probability,

P(B | A) = P(A ∩ B)/P(A) = (13/25) / (13/20) = 20/25 = 4/5

4 0
3 years ago
3x – 2y = 17 <br> –2x – 5y = 14 <br> Solve using Elimination Please show work
OleMash [197]

Answer:

The solution is x=3 , y=-4 or (3,-4)

Step-by-step explanation:

Given equations (1 and 2) are:

3x- 2y = 17\\-2x -5y = 14

To solve a system of equation with elimination method, the co-efficients of one of the variables has to be equated and then the equations are added or subtracted to get an equation in one variable.

Multiplying equation 1 by 2:

2(3x-2y) = 2*17\\6x-4y = 34\ \ \ \ \ Eqn\ 3

Multiplying equation 2 by 3

3(-2x-5y) = 3*14\\-6x-15y = 42\ \ \ \ Eqn\ 4

Adding equation 3 and 4

(6x-4y) + (-6x-15y) = 34+42\\6x-4y-6x-15y = 76\\-19y = 76\\\frac{-19y}{-19} = \frac{76}{-19}\\y = -4\\

Putting y = -4 in equation 1

3x-2(-4) = 17\\3x+8 = 17\\3x = 17-8\\3x = 9\\\frac{3x}{3} = \frac{9}{3}\\x = 3

Hence,

The solution is x=3 , y=-4 or (3,-4)

3 0
2 years ago
Two lines, A and B, are represented by the following equations: Line A: y = x − 1 Line B: y = −3x + 11 Which of the following op
OleMash [197]
1) The last one is correct.
6 0
2 years ago
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