If 1/4 serves 2 people, 6/4 or 1 pound and a half would serve 12 people
The answer is <span>The liquid must be in the cooler fewer than 10 minutes.
</span>
Let:
m - the number of minutes the liquid is in the cooler.
a - the starting temperature
The function is:
f(m) = a - 3 * m (Since the temperature decreases by 3°F each minute m, it has a negative sign)
Let:
m - <span>the number of minutes the liquid is in the cooler.
a - the starting temperature
</span>a = 90<span>°F
</span>
<span>The temperature of a liquid must stay above 60°F:
f(m) > 60
Thus:
</span>f(m) = a - 3 * m
f(m) > 60
a - 3 * m > 60
90 - 3m > 60
90 - 60 > 3m
30 > 3 m
30/3 > m
10 > m
Or m < 10. So the correct answer is The liquid must be in the cooler fewer than 10 minutes.
Answer:
209.55in²
Step-by-step explanation:
Find area of sector CADE
Radius =22 in
Angle=90°
Formula to apply is ;
Ф/360 × π × r² where
Ф=angle of sector, π=3.142 and r =radius of circle
Find area of triangle CAD where base length is 22 inches and height is 22 inches
Area of triangle formula is;
1/2×b×h where b is base and h is height
Find area remaining
380.182-242=138.182in²
Find the area of sector CBDF
Radius=28in
Angle=60°
Formula to apply is ;
Ф/360 × π × r² where
Ф=angle of sector, π=3.142 and r =radius of circle
Area of triangle BDC
The formula to apply is
1/2×a×a×sinФ where a=28 inches and Ф=60°
Remaining area
410.55-339.48=71.075in²
Area created by overlapping circles
138.182+71.075=209.26in²
Answer:
x = -2, y = 21
Step-by-step explanation:
Let 4x + y = 13 to be equation1 {eqn1}
and let 5x - y = 5 to be equation2 {eqn2}
Using elimination method, you would try to make sure a particular unknown has the same value in both equation 1 and 2. This would make it easy for you to subtract one equation from the other.
Notice how the value of y is the same in both equations. That's a good sign.
But the signs aren't the same. Meaning y in eqn1 has a value of +1, and y in eqn2 has a value of -1. We need to make them similar.
So, we multiply the value of y in eqn1 by all the terms in eqn2. And, do pretty much the same thing by multiplying the value of y in eqn2 by all the terms in eqn1.
You would have:
-1 * (4x + y = 13)
+1 * (5x - y = 5)
This would result in;
-4x - y = -13 (eqn3)
5x - y = 5 (eqn4)
So, just subtract eqn3 from 4
You would have;
(5x - -4x) + (-y -- y) = (-13 - 5)
9x + 0 = -18
x = -18/9 = -2
and to find y;
just substitute the value of x into any of the 4 equations. let's try equation 1
Therefore;
4(-2) + y = 13
-8 + y = 13
y = 13 + 8 = 21
