- A school is using 12 passenger vans to transport

Sometimes integers are encoded by using four-digit binary expansions to represent each decimal digit. this produces the binary c

wolverine [178]

<span>You're wasting a whole lot of possible 'space' in that encoding solution, but the answer is 4n. </span>

4 0

4 years ago

Can someone please help me brainlist to whoever gets it right

Nitella [24]

Domain and Range both are real numbers for all odd-degree polynomial functions.

Writing in an Interval Form, note that we use the least value in the left and the most value in the right.

From [a,b], [a,b), (a,b] or (a,b) | a must be less than b.

Therefore, the D choice is wrong in Interval part (However, right in range and domain but just for interval order.)

So the answer is C.

3 0

3 years ago

Calculus piecewise function.

Kipish [7]

Part A

The notation $\lim_{x \to 2^{+}}f(x)$ means that we're approaching x = 2 from the right hand side (aka positive side). This is known as a right hand limit.

So we could start at say x = 2.5 and get closer to 2 by getting to x = 2.4 then to x = 2.3 then 2.2, 2.1, 2.01, 2.001, etc

We don't actually arrive at x = 2 itself. We simply move closer and closer.

Since we're on the positive or right hand side of 2, this means we go with the rule involving x > 2

Therefore f(x) = (x/2) + 1

Plug in x = 2 to find that...

f(x) = (x/2) + 1

f(2) = (2/2) + 1

f(2) = 2

This shows $\lim_{x \to 2^{+}}f(x) = 2$

Then for the left hand limit $\lim_{x \to 2^{-}}f(x)$ , we'll involve x < 2 and we go for the first piece. So,

f(x) = 3-x

f(2) = 3-2

f(2) = 1

Therefore, $\lim_{x \to 2^{-}}f(x) = 1$

===============================================================

Part B

Because $\lim_{x \to 2^{+}}f(x) \ne \lim_{x \to 2^{-}}f(x)$ this means that the limit $\lim_{x \to 2}f(x)$ does not exist.

If you are a visual learner, check out the graph below of the piecewise function. Notice the gap or disconnect at x = 2. This can be thought of as two roads that are disconnected. There's no way for a car to go from one road to the other. Because of this disconnect, the limit doesn't exist at x = 2.

===============================================================

Part C

You'll follow the same type of steps shown in part A.

However, keep in mind that x = 4 is above x = 2, so we'll deal with x > 2 only.

So you'd only involve the second piece f(x) = (x/2) + 1

You should find that f(4) = 3, and that both left and right hand limits equal this value. The left and right hand limits approach the same y value. The limit does exist here. There are no gaps to worry about when x = 4.

===============================================================

Part D

As mentioned earlier, since $\lim_{x \to 4^{+}}f(x) = \lim_{x \to 4^{-}}f(x) = 3$ , this means the limit $\lim_{x \to 4}f(x)$ does exist and it's equal to 3.

As x gets closer and closer to 4, the y values are approaching 3. This applies to both directions.

4 0

2 years ago

Question 3 of

Rufina [12.5K]

With respect to the parent function y = cos x, the interval closest to the range of the transformed function is ( 0,50). the correct option is D.

<h3>How to find the functions corresponding to each graph based on the period of a function?</h3>

Mathematically speaking, cosines are periodic functions, and period (T) is the distance in the horizontal axis such that f(t + T) = f(t). The period of the parent cosine function is 2π. The period in daughter functions may vary by means of the following form:

y = cos Ax (1)

Where:

x - Independent variable

y - Dependent variable

A - Period width

From the graph, it is observed that with respect to the parent function y = cos x, the interval closest to the range of the transformed function is ( 0,50). the correct option is D.

To know more about parent functions follow brainly.com/question/26369761

#SPJ1

3 0

2 years ago

Please help with numbers 5, 6, 7, and 8 (Will give brainliest)

Harrizon [31]

Answer:

#5

If AB = BC, then BC = AB
Symmetric property of equality

#6

∠A = ∠A
Reflexive property of equality

#7

If 2x - 5 + 3x = 10 ⇒ add up 2x and 3x ⇒ then 5x - 5 = 10
Associative property of addition

#8

If B is the midpoint of AC, then AB = BC
Definition of midpoint

4 0

3 years ago