9514 1404 393
Answer:
A. 3×3
B. [0, 1, 5]
C. (rows, columns) = (# equations, # variables) for matrix A; vector x remains unchanged; vector b has a row for each equation.
Step-by-step explanation:
A. The matrix A has a row for each equation and a column for each variable. The entries in each column of a given row are the coefficients of the corresponding variable in the equation the row represents. If the variable is missing, its coefficient is zero.
This system of equations has 3 equations in 3 variables, so matrix A has dimensions ...
A dimensions = (rows, columns) = (# equations, # variables) = (3, 3)
Matrix A is 3×3.
__
B. The second row of A represents the second equation:

The coefficients of the variables are 0, 1, 5. These are the entries in row 2 of matrix A.
__
C. As stated in part A, the size of matrix A will match the number of equations and variables in the system. If the number of variables remains the same, the number of rows of A (and b) will reflect the number of equations. (The number of columns of A (and rows of x) will reflect the number of variables.)
Answer:
D. 3x² + 19x - 14
Step-by-step explanation:
Use FOIL to find the answer.
First: x * 3x = 3x²
Outer: -2 * x = -2x
Inner: 3x * 7 = 21x
Last: 7 * -2 = -14
Form the equation:
3x² - 2x + 21x - 14
Combine like terms.
3x² + 19x - 14
Answer:
Explanation:
First we find what x is:
x + 1/x = 12
x + 1 = 12x
1 = 12x - x
1 = 11x
1/11 = x
Or x = 1/11
Plug x value in x^3 + 1/x^3
(1/11)^3 + 1/(1/11)^3
= (1^3/11^3)+ 1/(1^3/11^3)
= (1/1331 + 1)/1/1331
= (1/1331 + 1331/1331)/1/1331
= 1332/1331 x 1331/1
= 1332/1
= 1332
Therefore, x^3 + 1/x^3 = 1332
Answer:
Step-by-step explanation:
The fruit store sells 10,000 apples....
it sells 1/2 apples per day......
what is half of 10,000? It’s 5,000
so, I think it’s 5,000.... I don’t know bc it does not tell how many days........
Answer:
D. (0, 3)
Step-by-step explanation: