#1. B
<span>(z * z^2 + z * 2z + z * 4) – (-2 *z^2 – (-2) 2z – (-2) 4)
Z^3 + 2z^2 + 4z – 2z^2 -4z – 8
Z^3 + 2z^2 – 2z^2 + 4z – 4z – 8
Z^3 - 8
</span>
#2 and #3. D
<span>(x + y)(x + 2)
x^2 + 2x + yx + 2y
</span>
#4. D.
<span>(x - 7)(x + 7)(x- 2)
x^2 + 7x – 7x -49
x^2 + x – 49
x^2 -49
(x^2 – 49 ) (x – 2)
x^3 – 2x^2 – 49x + 98
</span>
#5. C
(y - 4) = 0
y = 4
(x + 3)= 0
x = -3
#6. A and B
Answer: 49
Step-by-step explanation:
50−16/4+3
=50−4+3
=46+3
=49
Answer:
3.3 LBS
Step-by-step explanation:
33 pounds for 10 cups
33/10
3.3
Maybe you thought about this:
m^2+6m-77+5=0 => m^2+6m-72=0 => m^2+ 2*3*m+3^2-3^2-72=0
=> m^2+2*3*x+3^2= (m+3)^2 this is the complete square of the binomial, we will still keep it =>
(m+3)^2 -9 -72=0 => (m+3)^2 - 81 = 0 => (m+3)^2 - 9^2 = 0
Now we got the difference squares, it mean a^2 - b^2 = (a-b) (a+b)
In according to this => (m+3-9) (m+3+9) = 0 =>
(m-6) (m+12)=0 => m-6=0 or m+12=0 => m1=6 or m2= -12 !!!!
Are you satisfied with this solution?
