Question

A squirrel climbs up a tree. She starts at 0.5 feet up the tree, then climbs at a steady pace for 7.5 seconds. She ends 4 feet up the tree. How many feet did she climb per second? A. 7.5 + 1 2 x = 4 B. 1 2 + 4 x = 7.5 C. 4 + 1 2 x = 7.5 D. 7.5 x + 1 2 = 4

Answer 1

Given :

A squirrel climbs up a tree. She starts at 0.5 feet up the tree, then climbs at a steady pace for 7.5 seconds.

She ends 4 feet up the tree.

Solution :

Now, distance covered is :

d = 4 - 0.5 = 3.5 feet.

Time taken, t = 7.5 seconds.

Distance climbed per second is :

$D =\dfrac{d}{t}\\\\D=\dfrac{3.5}{7.5}\\\\D = 0.467\ feet/s$

Therefore, distance climber per second is 0.467 feet.

Hence, this is the required solution.